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Ivanshal [37]
2 years ago
14

Zoe made 6 3/4 cups of fruit salad for a picnic at the picnic they ate 1/3 of the fruit salad how much fruit salad did they eat

Mathematics
1 answer:
yanalaym [24]2 years ago
4 0

6 3/4 = 27/4

27/4 * 1/3 = 27/12

27/12 = 9/4

Answer: 9/4 cups

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What is 2 3/10 as a percent?
kobusy [5.1K]
2 3/10 = 2.3
To get this number as a percent, we need to multiply it by 100: 2.3 is a whole number, and can be represented by fraction 2.3/1
A percentage is represented by a fraction over 100. So to transform 2.3/1 to a percentage, just multiply both numerator and denominator by 100, and you'll get 230/100.
So 2 3/10 is 230% as a percent.

Hope this Helps! :)
4 0
3 years ago
Read 2 more answers
A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di
denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}

Now centripetal acceleration is given by

a_c=\frac{V^{2}}{R}

where V= 4.0\frac{m}{s}

Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m

\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}

Thus her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

4 0
3 years ago
Read 2 more answers
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
Please help me.!.!.!.!.!.
denis-greek [22]
Pretty sure it's right top corner 
4 0
2 years ago
Read 2 more answers
PLEASE HELP ME! Images below & I give Brainliest
neonofarm [45]

Answer:

Graph C with the green dots.

Step-by-step explanation:

y = 0.5x + 5 is a linear equation, so we can rule out A because it is not straight.

5 represents the y-intercept, so we rule out B because that graph doesn't intercept the y-axis at (0,5).

Graph C represents a straight line that passes through (0, 5) & has a 0.5 slope, so that is our answer.

Hope this helps. :0)

4 0
2 years ago
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