What would happen to the amount of matter on earth if mass were not conserved during changes of state?
Answer:
c. Kay's rule
Explanation:
Kay's rule -
The rule is used to determine the pseudo reduced critical parameters of mixture , with the help of using the critical properties of the components of a given mixture .
The equation for Kay's rule is as follows ,
PV = Z RT
Where Z = The compressibility factor of the mixture .
Hence from the given options , the correct answer is Kay's rule .
The final temperature inside the container is 77.5°C
<h3>Solution ; </h3>
There are two heat transfers involved:
heat lost by bolt 1 + heat gained by bolt 2 = 0
-q(heat released by iron bolt) at higher temperature = q(heat gained by iron bolt) at lower temperature
-(cm)(T2-Treat higher temperature) = (cm)(T2-Tre at lower temperature)
-[0.450/(J/g-K) × m × (T2 -100°C)] = [0.450/(J/g-K) × m × (T2 -55°C)]
Or, -(T2 - 100°C) (T2 - 55°C) T2+T2 = 100°C + 55°C
Or, T2 = 155°C /2 = 77.5°C
<h3>What is Specific Heat ?</h3>
Specific heat is the amount of heat necessary to increase the temperature of one gram of a substance by one degree Celsius. Specific heat is often measured in calories or joules per gram per Celsius degree. Water, for example, has a specific heat of one calorie (or 4.186 joules) per gram per Celsius degree.
To know more about Specific Heat please click here : brainly.com/question/21406849
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Answer:
a chemical change are a change in color and the formation of bubbles.
chemical change: color change, formation of a precipitate, formation of a gas, odor change, temperature change.
Explanation:
Change it up a little bit and your teacher will never know. :)
<u>Given:</u>
MilliMoles of N2 = 2.5 mmol = 0.0025 moles
Initial volume V1 = 42 cm3
Final volume V2 = 600 cm3
Temperature T = 300 K
<u>To determine:</u>
The change in Gibbs free energy, ΔG
<u>Explanation:</u>
The change in Gibbs free energy is related to the ration of the volumes:
ΔG = -nRTln(V2)/(V1)
= -0.0025*8.314*300*ln(600/42) = -16.582 J/mol
Ans: The Gibbs free energy for the process is 0.0166 kJ/mol