3 years ago

What would happen to the amount of matter on Earth if mass were not conserved during the changes on states?

Chemistry

1 answer:

Mademuasel [1]3 years ago

3 0

What would happen to the amount of matter on earth if mass were not conserved during changes of state?

You might be interested in

What is the molar mass of potassium bromide, KBR?

Nezavi [6.7K]

Answer:

id.............k

Explanation:

3 0

3 years ago

What is the colour change when universal indicator is added to apple juice

kherson [118]

Answer:

red because its the flavor

Explanation:

5 0

3 years ago

Read 2 more answers

Please help. im freaking out rn. i have like 40 missing assignments please

Katarina [22]

Answer:

I'm pretty sure its the one that says very little at the beginning but if I get it wrong I'm sorry

5 0

3 years ago

30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr

Alenkasestr [34]

Answer: Thus concentration of $Ca(OH)_2$ in $mol/dm^3$ is 0.011 and in $g/dm^3$ is 0.814

Explanation:

To calculate the concentration of $Ca(OH)_2$ , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3$ $1cm^3=0.001dm^3$

Putting values in above equation, we get:

$1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3$

The concentration in $g/dm^3$ is $0.011mol/dm^3\times 74g/mol=0.814g/dm^3$

Thus concentration of $Ca(OH)_2$ is $0.011mol/dm^3$ and $0.814g/dm^3$

4 0

3 years ago

Which of the following statements is NOT true of the Lewis Dot Diagrams?

vivado [14]

You tryna cheat? I think it’s four so hopefully not

7 0

3 years ago

Read 2 more answers