Question

A 4.0g sample of iron was heated from 0c to 20c. it absorbed 35.2j of energy as heat. what is the specific heat of this piece of iron

Answer 1

We are going to use the heat absorbed formula:

Q = M*C*ΔT

when Q is the heat absorbed = 35.2 J

and M is the mass of iron = 4 g 

and C is the specific heat capacity of iron (which we need to calculate)

ΔT the change in temperature = 20-0 = 20 °C

so, by substitution:

35.2 J = 4 g * C * 20°C

∴ the specific heat of this piece of iron C =  35.2 / (4g*20°C)


                                                                     = 0.44 J/g.°C