The time it takes for a ball to complete the trip is given to be 4.10 s. This implies that the trip going up of the ball is equal to 2.05 s. Using this time to determine the initial speed, we have,
Vf = Vo - gt
Vf is the final speed which is equal to 0 on the topmost location of the ball.
0 = Vo - (9.8 m/s²)(2.05 s)
Vo = 20.09 m/s
At 0.5 s,
Vf = 20.09 m/s - (9.8 m/s²)(0.5 s)
Vf = 15.19 m/s
Thus, the speed of the ball when the height is in level with the top of the flagpole is 15.19 m/s.
Answer:
80 <em>B</em><em>r</em><em>i</em><em>e</em><em>f</em><em>l</em><em>y</em>
Explanation:
sorry yan lang po ang alam ko
<em>a</em><em>n</em><em>d</em><em> </em><em>t</em><em>h</em><em>a</em><em>n</em><em>k</em><em>s</em><em> </em><em>t</em><em>o</em><em> </em><em>p</em><em>o</em><em>i</em><em>n</em><em>t</em><em>s</em><em> </em><em>☺</em>
Frequency of the wave is 2 per second
Explanation:
- Frequency is the number of times waves pass at a particular point of time. Here, given time period = 3 s and number of waves that pass in 3 seconds = 6. Find the frequency of the wave per second.
- Frequency is given by the formula
f = 1/T, where f is the frequency and T is the time period
- For 3 seconds, frequency is 6
3 seconds ⇒ 6 waves
⇒ 1 second = 6/3 = 2 waves per second
What a delightful little problem !
Here's how I see it:
When 'C' is touched to 'A', charge flows to 'C' until the two of them are equally charged. So now, 'A' has half of its original charge, and 'C' has the other half.
Then, when 'C' is touched to 'B', charge flows to it until the two of <u>them</u> are equally charged. How much is that ? Well, just before they touch, 'C' has half of an original charge, and 'B' has a full one, so 1/4 of an original charge flows from 'B' to 'C', and then each of them has 3/4 of an original charge.
To review what we have now: 'A' has 1/2 of its original charge, and 'B' has 3/4 of it.
The force between any two charges is:
F = (a constant) x (one charge) x (the other one) / (the distance between them)².
For 'A' and 'B', the distance doesn't change, so we can leave that out of our formula.
The original force between them was 3 = (some constant) x (1 charge) x (1 charge).
The new force between them is F = (the same constant) x (1/2) x (3/4) .
Divide the first equation by the second one, and you have a proportion:
3 / F = 1 / ( 1/2 x 3/4 )
Cross-multiply this proportion:
3 (1/2 x 3/4) = F
F = 3/2 x 3/4 = 9/8 = <em>1.125 newton</em>.
That's my story, and I'm sticking to it.
Answer:
It corresponds to a distance of 100 parsecs away from Earth.
Explanation:
The angle due to the change in position of a nearby object against the background stars it is known as parallax.
It is defined in a analytic way as it follows:
Where d is the distance to the star.
(1)
Equation (1) can be rewritten in terms of d:
(2)
Equation (2) represents the distance in a unit known as parsec (pc).
The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth (as is shown in the image below), knowing that the distance between the Earth and the Sun (150000000 Km), is defined as 1 astronomical unit (1AU).
For the case of ():
Hence, it corresponds to a distance of 100 parsecs away from Earth.
<em>Summary:</em>
Notice how a small parallax angle means that the object is farther away.
Key terms:
Parsec: Parallax of arc second