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3 years ago

Why do scientists use the International System of Units

1 answer:

german3 years ago

7 0

Here is my input:
because the International System of Units is based on the metric system which is used worldwide.

Hope this helps.

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A large crate is at rest on a horizontal floor. The coefficient of static friction between the crate and the floor is 0.500. A f

Nookie1986 [14]

Answer:

93.4 kg

Explanation:

Draw a free body diagram. There are three four forces:

Weight force mg pulling down,

Normal force N pushing up,

Friction force Nμ pushing left,

Applied force F pulling up and to the right, 30.0° above the horizontal.

Sum of forces in the y direction:

∑F = ma

N + F sin 30.0° − mg = 0

N = mg − ½ F

Sum of forces in the x direction:

∑F = ma

F cos 30.0° − Nμ = 0

½√3 F = Nμ

Substitute:

½√3 F = (mg − ½ F) μ

½√3 F / μ = mg − ½ F

½√3 F / μ + ½ F = mg

½F (√3 / μ + 1) = mg

m = F (√3 / μ + 1) / (2g)

Plug in values:

m = 410 N (√3 / 0.500 + 1) / (2 × 9.8 m/s²)

m = 93.4 kg

4 0

3 years ago

Read 2 more answers

You have a spool of copper wire 4.82 mm in diameter and a power supply. You decide to wrap the wire tightly around a soda can th

GalinKa [24]

To solve the problem it is necessary to have the concepts of the magnetic field in a toroid.

A magnetic field is a vector field that describes the magnetic influence of electric charges in relative motion and magnetized materials.

By definition the magnetic field is given by the equation,

$B=\frac{\mu_0 NI}{2\pi r}$

Where,

$\mu_0$ = Permeability constant

N = Number of loops

I = Current

r = Radius

According to the given data we have that the length is 120mm and the thickness of the copper wire is 4.82mm.

In this way the number of turns N would be

$N=\frac{120mm}{4.82mm}$

$N = 24.89 \approx 25 turns$

On the other hand to find the internal radius, we know that:

$2\pi r_i = 12cm$

$r_i= \frac{12}{2\pi}$

$r_i= 1.91cm$

Therefore the total diameter of the soda would be

$r= r_i+r_o = 1.91+6.5=8.51cm$

Applying the concept related to magnetic field you have to for the internal part:

$B_i=\frac{\mu_0 NI}{2\pi r_i}$

$B_i=\frac{(4\pi*10^{-7}) (25)(230)}{2\pi (1.91*10^{-2})}$

$B_i = 0.060T$

The smallest magnetic field would be on the outside given by,

$B_o=\frac{\mu_0 NI}{2\pi r}$

$B_o=\frac{(4\pi*10^{-7}) (25)(230)}{2\pi 8.51}$

$B_o = 0.0136T$

<em>Therefore the maximum magnetic field is 0.06T.</em>

4 0

4 years ago

When you blow across the top of

Tanya [424]

Answer:

the new foundation would be

Explanation:

4 0

3 years ago

find the area of a right triangle with sides 15.0 cm, 20.0 cm, and 25.0 cm. express your answer with the correct number of signi

pickupchik [31]

The area of this triangle can be calculated using herons formula since th three sides are given. It is expressed as:

A=sqrt( s(s-a)(s-b)(s-c))

where s is equal to a+b+c / 2

s=15 +20 +25 /2=30
A=sqrt( 30(30-15)(30-20)(30-25))
A= 150 cm^3

4 0

3 years ago

What is the transfer of energy to a system by the application of a force called?

pav-90 [236]

It is called Work done

6 0

3 years ago