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Physics

1 answer:

Evgesh-ka [11]3 years ago

4 0

Answer:D 780,000,000km

Explanation:

1 AU is the distance of the sun to the earth and this value is 150,000,000km

Jupiter's distance from the sun is 5.2AU and is equivalent in km is:

5.2AU × 150,000,000Km= 780,000,000km

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Answer:

Explanation:

$\lambda$ = Observed wavelength = 550 nm

$\lambda'$ = Actual wavelength = 635 nm

c = Speed of light = $3\times 10^8\ \text{m/s}$

v = Velocity of the physicist

Doppler shift is given by

$f=\sqrt{\dfrac{c+v}{c-v}}f'\\\Rightarrow \dfrac{c}{\lambda}=\sqrt{\dfrac{c+v}{c-v}}\dfrac{c}{\lambda'}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}=\dfrac{c+v}{c-v}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}=\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}(1-\dfrac{v}{c})=1+\dfrac{v}{c}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}(1-\dfrac{v}{c})=1+\dfrac{v}{c}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}-1=\dfrac{v}{c}(1+\dfrac{\lambda'^2}{\lambda^2})\\\Rightarrow v=\dfrac{c(\dfrac{\lambda'^2}{\lambda^2}-1)}{1+\dfrac{\lambda'^2}{\lambda^2}}$