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mixas84 [53]
3 years ago
12

Help meeeeeeeeeeee!!!!

Physics
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:D 780,000,000km

Explanation:

1 AU is the distance of the sun to the earth and this value is 150,000,000km

Jupiter's distance from the sun is 5.2AU and is equivalent in km is:

5.2AU × 150,000,000Km= 780,000,000km

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A 0.2 kg block sliding on a horizontal table slows down from 25 m/s to 20 m/s. How much energy does the block lose due to fricti
Papessa [141]

Answer:

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Explanation:

Given;

mass of the block, m = 0.2 kg

initial velocity of the block, u = 25 m/s

final velocity of the block, v = 20 m/s

The kinetic energy lost due to friction is calculated as;

\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 -  \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J

Therefore, the kinetic energy lost due to friction is 22.5 J

7 0
3 years ago
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Alisiya [41]

1.46m/s²

Explanation:

Given parameters:

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Unknown:

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Since acceleration of the cart is unknown;

     Acceleration = \frac{force}{mass} = \frac{411}{281}

  Acceleration = 1.46m/s²

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

8 0
3 years ago
Which factors affect friction between two solid surfaces?
a_sh-v [17]
1) newton of the surfaces in contact (the smoothness of the surfaces)

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blagie [28]
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