Explanation:
Maybe your phone is being slow. Turn of your data and turn it back on
Answer:
21.6 kw
Explanation:
Given data:
m = 50 kg/s
Inlet pressure (p1) = 2 bar
outlet pressure(p2) = 6.2 bar
suction ( h1 ) = -2.2 m
delivery ( h2 ) = 8.5 m
d1 = 200 mm = 0.2 m
d2 = 100 mm = 0.1 m
Vs of water = 0.001 m^3/kg
next we have to determine the Q value
Q = V*A
Q = 0.001 * 50 = 0.05 m^3/s
next we have to calculate the various V's
V1 = Q/A1 = 
= 1.59 m/s
V2 = Q/A2 = 
= 6.37 m/s
Determine the capacity of the electric motor
attached below is the detailed solution
Answer:
Many circuits also contain capacitors and inductors, in addition to resistors and ... (a) Calculate the inductive reactance of a 3.00 mH inductor when 60.0 Hz and ... Part a of the figure shows a capacitor C connected across an A C voltage source V .... 5: (a) Find the current through a 0.500 H inductor connected to a 60.0 Hz, ...
Explanation:
hope this helps
Answer:
The question is a problem that requires the principles of fracture mechanics.
and we will need this equation below to get the Max. Stress that exist at the tip of an internal crack.
Explanation:
Max Stress, σ = 2σ₀√(α/ρ)
where,
σ₀ = Tensile stress = 190MPa = 1.9x10⁸Pa
α = Length of the cracked surface = (4.5x10⁻²mm)/2 = 2.25x10⁻⁵m
ρ = Radius of curvature of the cracked surface = 5x10⁻⁴mm = 5x10⁻⁷m
Max Stress, σ = 2 x 1.9x10⁸ x (2.25x10⁻⁵/5x10⁻⁷)⁰°⁵
Max Stress, σ = 2 x 1.9x10⁸ x 6.708 Pa
Max Stress, σ = 2549MPa
Hence, the magnitude of the maximum stress that exists at the tip of an internal crack = 2549MPa
