Answer:
There is not going to be pressure build up in the system,that is isobaric process.
Explanation:
Assumptions to be made
1. No mass is gained or lost during the heating process.
2. There are no friction losses,so work is transmitted efficiently.
3. It was started the water in the drum and its surrounding have same temperature.
4. This system is closed,so there is no mass transfer across its boundaries.
Answer:
using calculations Heat losses will be 4512 J
Answer:
Elastic modulus of steel = 202.27 GPa
Explanation:
given data
long = 110 mm = 0.11 m
cross section 22 mm = 0.022 m
load = 89,000 N
elongation = 0.10 mm = 1 ×
m
solution
we know that Elastic modulus is express as
Elastic modulus =
................1
here stress is
Stress =
.................2
Area = (0.022)²
and
Strain =
.............3
so here put value in equation 1 we get
Elastic modulus =
Elastic modulus of steel = 202.27 ×
Pa
Elastic modulus of steel = 202.27 GPa
Answer:
Determine the added thrust required during water scooping, as a function of aircraft speed, for a reasonable range of speeds.= 132.26∪
Explanation:
check attached files for explanation
The impact behavior of plastic materials is strongly dependent upon the temperature. At high temperatures, materials are more ductile and have high impact toughness. At low temperatures, some plastics that would be ductile at room temperature become brittle.