The
equilibrium constant is a value which represents the equilibrium of a reaction.
It is a reaction quotient when the reaction reached equilibrium. The reaction in the system is expressed as:
<span>H2 + I2 = 2HI
we express Keq as follows:
Keq = [HI]^2 / [H2] [I2]
Where the terms represents the concentrations of
the substances involved. THe concentrations are as follows:</span>
<span>H2 = 0.763 ( 1 / 18.02) / 3.67 = 0.0115 M</span>
<span>I2 = 96.9 ( 1 / 253.8) / 3.67 = 0.1040 M</span>
<span>HI (at equilibrium) = 90.4 ( 1 / 127.91) / 3.67 = 0.1956 M</span>
<span>
By the ICE table, we can calculate the
equilibrium concentrations,
H2 I2 HI
I 0.0115 0.1040 0
C -x -x +2x
-----------------------------------------------------------
E 0.0115-0.0963 0.1040-0.0963 0.1926 ===> x = 0.0963
Keq = (</span>0.1926<span>)^2 / (0.0077) (0.0848)
Keq = 56.81</span>
The mass of the sample of the material is 0.1664 g.
<h3 /><h3>What is specific heat?</h3>
The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.
By the formula of specific heat
Given, that the specific heat (c) of material is 0.416 J/gC
The difference in temperatures is 30°C to 50°C
The mass=?
Q = heat, 50 J
Putting the values in the equation
Thus, the mass of the samples is 0.166 g.
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The ph of the buffer solution is 7.743.
What is the Henderson-Hasselbalch Equation?
The Henderson-Hasselbalch equation establishes a relationship between the pKa and pH of acids. When the concentration of the acid and its conjugate base and the associated conjugate acid, are known, the pH of a buffer solution can be determined with the use of this equation.
We use Henderson-hasselbalch equation,
pH = pKa + log [Base] / [Acid]
pKa = -log Ka = -log (3.0 x 10^-8) = 7.46
pH = 7.52 + log [0.250] / [0.150]
pH = 7.52+ 0.2227
pH = 7.743
Therefore, the ph of the solution is 7.743.
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Answer:
SO3
Explanation:
Data obtained from the question include:
S = 40%
O = 59%
To obtain the empirical formula, do the following:
Divide the above by their molar mass as shown below:
S = 40/32 = 1.25
O = 59/16 = 3.69
Next, divide by the smallest as shown below:
S = 1.25/125 = 1
O = 3.69/1.25 = 3
Therefore, the empirical formula is SO3