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BlackZzzverrR [31]
3 years ago
12

What will happen if you take a frog out of the food chain?

Chemistry
1 answer:
Setler [38]3 years ago
4 0
<span>there are a number of animals that eat  frogs that will die off, then the animals that eat them will go hungry, and their populations will die off as well. This would just keep going up the food chain. Essentially, the loss of the frogs could have deep, reverberating effects that we may not grasp until it’s too late.</span>
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Which statement is always true about conversation of matter?
Firlakuza [10]

Answer:

The mass of a system does not change during a chemical reaction

Explanation:

Correct Answers

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What questions, if we were to answer them, would
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Explanation:

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2 years ago
Which example is a renewable energy source?
Ierofanga [76]
Sunlight is collected from a renewable resource, which is naturally replenished one a human timescale
4 0
3 years ago
Read 2 more answers
The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleane
GenaCL600 [577]

Answer : The total mass of oxygen gas released in the reaction will be, 12.8 grams

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2MgO\rightarrow 2Mg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2MgO = Total mass of 2Mg+O_2

or,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

As we are given :

Total mass of MgO = 16.12 grams

The mass of Mg = 9.72 grams

So,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

2\times 16.12g=2\times 9.72g+\text{Mass of }O_2

\text{Mass of }O_2=32.24g-19.44g=12.8g

Therefore, the total mass of oxygen gas released in the reaction will be, 12.8 grams

8 0
3 years ago
What is the empirical formula of a molecule containing 65.5% carbon, 5.5% hydrogen, and 29.0% oxygen
natta225 [31]
Carbon(C):
number of moles= mass/molar mass(Mr)
=65.5/12
=5.5 moles

Hydrogen(H):
number of moles=mass/molar mass (Mr)
=5.5/1
=5.5 moles

Oxygen (O):
number of moles = mass/molar mass (Mr)
=29.0/16
=1.8 moles

EF= lowest number of moles over each of the elements

So,
C= 5.5/1.8 = 3
H= 5.5/1.8 = 3
O= 1.8/1.8 = 1

Therefore Emperical formula= C3H3O
6 0
2 years ago
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