Which fraction converts to a repeating decimal number?

A adult blinks about 450 times every 30 minutes. a 12 year old blinks about 150 times every 15 minutes. how many more times does

ahrayia [7]

An adult blinks 300 times more in an hour

4 0

4 years ago

Find the mean and standard deviation for the set of data.

dem82 [27]

The mean and standard deviation for the set of data will be 16 and 5.87. Then the correct option is A.

<h3>What is a standard deviation?</h3>

It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.

The set of data is given below.

16, 22, 8, 5, 20, 18, 14, 17, 24

The mean of the data set will be

μ = (16 + 22 + 8 + 5 + 20 + 18 + 14 + 17 + 24) / 9

μ = 144 / 9

μ = 16

Then the standard deviation of the data set will be

$\rm \sigma = \sqrt{\dfrac{\Sigma (x_i - \mu)^2}{n}} \\\sigma = \sqrt{\dfrac{(16 - 16)^2 +(22 - 16)^2 + (8-16)^2 + ......+(24-16)^2 }{9}} \\\sigma = \sqrt{\dfrac{310}{9}}\\$

Simplify the expression further, then we have

σ = √34.44

σ = 5.87

The mean and standard deviation for the set of data will be 16 and 5.87.

Then the correct option is A.

More about the standard deviation link is given below.

brainly.com/question/12402189

#SPJ1

3 0

1 year ago

What is the answer to 4÷8/12

lawyer [7]

Answer:

2/12

PLZ tell me if I am wrong because am not usually to good at math

5 0

3 years ago

A company purchases a small metal bracket in containers of 5,000 each. Ten containers have arrived at the unloading facility, an

MariettaO [177]

Answer:

Do the data from this shipment indicate statistical control: No

Step-by-step explanation:

Calculating the mean of the sample, we have;

Mean (x-bar) = sum of individual sample/number of sample

= (0+0+0+0.004+0.008+0.020+0.004+0+0+0.008)/10

= 0.044/10

= 0.0044

Calculating the lower control limit (LCL) using the formula;

LCL= (x-bar) - 3*√(x-bar(1-x-bar))/n

= 0.0044 - 3*√(0.0044(1-0.0044))

= 0.0044- (3*0.0042)

= 0.0044 - 0.01256

= -0.00816 ∠ 0

Calculating the upper control limit (UCL) using the formula;

UCL = (x-bar) + 3*√(x-bar(1-x-bar))/n

= 0.0044 + 3*√(0.0044(1-0.0044))

= 0.0044+ (3*0.0042)

= 0.0044 + 0.01256

=0.01696∠ 0

Do the data from this shipment indicate statistical control: No

Since the value 0.02 from the 6th shipment is greater than the upper control limit (0.01696), we can conclude that the data from this shipment do not indicate statistical control.

8 0

3 years ago

Solve #3 Find the length of the missing side.a) A right triangle has a side length 2.4 cm and 6.5 cm. What is the length of the

Snezhnost [94]

Answer:

A) ≈ 6.93

B) ≈ 0.02

Step-by-step explanation:

A)

Formula : a² + b² = c²

2.4² + 6.5² = c²

5.76 + 42.25 = c²

c = √48.01

c ≈ 6.93

B)

Formula = c² - a² = b²

1/3² - 1/4² = b²

1/9 - 1/16 = b²

b = √7/144

b ≈ 0.02

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0

3 years ago

Read 2 more answers