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Lana71 [14]
1 year ago
8

Can someone please help me

Mathematics
1 answer:
rewona [7]1 year ago
4 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: f(0) = -3

\qquad \tt \rightarrow \: f(2) = 1

\qquad \tt \rightarrow \: f(4) = 1

____________________________________

\large \tt Solution  \: :

F(x) represents the value of y on curve for given value of x

\textsf{\large First -}

\qquad \tt \rightarrow \: f(0) =( 0) {}^{2}  - 3

[ since 0 < 2 ]

\qquad \tt \rightarrow \: f(0) = 0 {}^{}  - 3

\qquad \tt \rightarrow \: f(0) =   - 3

\textsf{\large Second}

\qquad \tt \rightarrow \: f(2) =   (2) {}^{2}  - 3

[ since 2 = 2 ]

\qquad \tt \rightarrow \: f(2) =   4{}^{}  - 3

\qquad \tt \rightarrow \: f(2) =   1

\textsf{\large Third -}

\qquad \tt \rightarrow \: f(4) =    - 4 + 5

[ since 4 > 2 ]

\qquad \tt \rightarrow \: f(4) =    1

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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3 years ago
The length of a rectangle is 2 ft longer than its width.
tino4ka555 [31]

Hi! I'm happy to help!

To solve this, we first need to look at the perimeter equation:

P=2L+2W

We don't know our length, so we can represent it with x. Since our width is 2 feet shorter than x, we can represent it with x-2. Now, we plug these values into our equation:

56=2x+(2(x-2))

Let's simplify what the width is by multiplying:

56=2x+2x-4

Now, let's combine our 2xs

56=4x-4

Now, we just need to solve for x in order to find our length and width.

First, we need to isolate x on one side of the equation. We can do this by adding 4 to both sides:

56=4x-4

+4      +4

60=4x

Now, all we have to do is divide both sides by 4 and x will be fully isolated:

60=4x

÷4  ÷4

15=x

Now that we know x, let's plug this into our previous equations:

L=x=15

<u>L=15</u>

W=x-2=15-2=13

<u>W=13</u>

To verify our answers, we can plug this into our perimeter equation:

56=2(15)+2(13)

56=30+36

56=56

After double checking our answers, we know that our length is 15 and our width is 13.

I hope this was helpful, keep learning! :D

5 0
2 years ago
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