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Leviafan [203]
3 years ago
5

25 points! pls show work if can!!!!!!!!

Mathematics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

A.2.4 pounds

B.7 oranges

Step-by-step explanation:

Nataliya [291]3 years ago
3 0

Answer: 8.4

Step-by-step explanation:

15-6.6

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Given the function f(x) = 20(1.25)^x . what is the average rate of change between f(2) and f(5)
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The average rate of change of f(x) on the interval [a,b] is f(b)−f(a)b−a.

We have that a=1254, b=6103100, f(x)=20(54)x.

Thus, f(b)−f(a)b−a=20(54)(6103100)−(20(54)(1254))6103100−(1254)=−58207660913467407226562517167001203595951472642–√5–√4+542101086242752217003726400434970855712890625197922048572373973475376871275743307366424750⋅53100.

Answer: the average rate of change is −58207660913467407226562517167001203595951472642–√5–√4+542101086242752217003726400434970855712890625197922048572373973475376871275743307366424750⋅53100≈550754.870532511

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