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Harlamova29_29 [7]
3 years ago
6

State three means of operating a power tool

Engineering
1 answer:
nadya68 [22]3 years ago
5 0
Compressed or air electricity or combustion.
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The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel. Determine the magnitude of forc
Sonbull [250]

Answer:

Magnitude of force P = 25715.1517 N

Explanation:

Given - The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel.

To find - Determine the magnitude of force P so that the rigid beam tilts 0.015∘.

Proof -

Given that,

Diameter = 12 mm = 0.012 m

Length = 0.6 m

\theta = 0.015°

Youngs modulus of elasticity of 34 stainless steel is 193 GPa

Now,

By applying the conditions of equilibrium, we have

∑fₓ = 0, ∑f_{y} = 0, ∑M = 0

If ∑M_{A} = 0

⇒F_{BC}×0.9 - P × 0.6 = 0

⇒F_{BC}×3 - P × 2 = 0

⇒F_{BC} = \frac{2P}{3}

If ∑M_{B} = 0

⇒F_{AD}×0.9 = P × 0.3

⇒F_{AD} ×3 = P

⇒F_{AD} = \frac{P}{3}

Now,

Area, A = \frac{\pi }{4} X (0.012)^{2} = 1.3097 × 10⁻⁴ m²

We know that,

Change in Length , \delta = \frac{P l}{A E}

Now,

\delta_{AD} = \frac{P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9}  } = 9.1626 × 10⁻⁹ P

\delta_{BC} = \frac{2P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9}  } = 1.83253 × 10⁻⁸ P

Given that,

\theta = 0.015°

⇒\theta = 2.618 × 10⁻⁴ rad

So,

\theta =  \frac{\delta_{BC} - \delta_{AD}}{0.9}

⇒2.618 × 10⁻⁴ = (  1.83253 × 10⁻⁸ P - 9.1626 × 10⁻⁹ P) / 0.9

⇒P = 25715.1517 N

∴ we get

Magnitude of force P = 25715.1517 N

6 0
3 years ago
On a summer day in New Orleans, Louisiana, the pressure is 1 atm: the temperature is 32°C; and the relative humidity is 95 perce
FinnZ [79.3K]

Answer:

Δw =7.95 kg/1000m^3

q = 62362.3 kg/1000m^3

Explanation:

To solve this problem we first need to use the psycrometric chart to determine the enthalpy h1, specific volume vi and absolute humidity col by using the given temperature T1 = 32°C and the relative humidity Ф1 = 95%.  

h_1 =  106.5 kJ/kg

v_1 = 0.91 m^3/kg

w_1 = 0.02905

We will also need the enthalpy h2 and the absolute humidity w_2 at the exit point. We will again use the pyscrometric chart and the given temperature T_2 = 24°C. From the problem we also know that the exit relative humidity is = 60%.  

h2 = 52.6 kJ/kg

w_2 = 0.01119

We need to express the final results in units per 1000 m^3. To do that we will need the mass m of this volume of air V and to calculate that we will use the given pressure p = 1 atm = 101.3 kPa.  

m = R_a*T_1/V.p

m = 1000*101.3/0.287*305K

m = 1157 kg

Because it is a closed system, the amount of water removed Δw can be calculated as:  

Δw =w_1 - w_2

Δw =0.02905- 0.01119

Δw =0.00687 kg/kg* 1157kg/1000m^3

Δw =7.95 kg/1000m^3

From the energy balance equation we can calculate the specific heat q removed from the air.  

q = h_1 - h_2

q = 106.5 kJ/kg - 52.6 kJ/kg

q = 53.9 kJ/kg * 1157kg/1000m^3

q = 62362.3 kg/1000m^3

3 0
4 years ago
When you walk down the street, your muscles are supplying you with the
Genrish500 [490]

Your muscles are supplying you with the energy to move through a biological process called <u>metabolism</u>.

<h3>What is metabolism?</h3>

Metabolism can be defined as a set of chemical and biological processes that are carried out by a living organism, in order to sustain life.

A good example of metabolism is the supply of energy by the muscles in the body of a living organism, which enables him or her to move from one point to another.

In conclusion, your muscles are able to supply you with the energy to move through a biological process called <u>metabolism</u>.

Read more on metabolism here: brainly.com/question/1490181

4 0
3 years ago
Air at a temperature of 333 °C flows with a velocity of 10 m/s over a flat plate 0.5m long. Estimate the cooling rate per unit w
Rama09 [41]

The answer & explanation for this question is given in the attachment below.

3 0
4 years ago
I need some one to help me for a quiz electronics this my insta (tu_rb) ​
Otrada [13]

Answer:

i dont want too

Explanation:

4 0
3 years ago
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