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Allisa [31]
3 years ago
13

Since 1990, hand-held mobile phones have been used as communication devices. Mobile phones have gone through a lot of design cha

nges over the years. Do online research and discuss the major changes in mobile phone designs in the last 20 years.
Engineering
1 answer:
Alexxx [7]3 years ago
8 0

Answer: IMPACT: Access to the mobile web was a major improvement for cell phones in the 1990s. With 2G (digital cellular networks), came the ability to access media content and the World Wide Web on cell phones.

Explanation:

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What’s the difference between quality and quantity
Lesechka [4]
Quality is how good something is. Like how good the material is. Like the quality of the IPhone X is better than the quality of the iPhone 6s + because it has more features and can sustain better hold
Quantity is how much. Like the quantity of the m&ms were split evenly.
I dont know exactly if that makes sense but there ya go
YW!
4 0
3 years ago
Read 2 more answers
A spherical hot air balloon is initially filled with air having 120 kPa pressure and 24 °C temperature. Initial diameter of the
tino4ka555 [31]

Answer:

v = 1.076 m /s

Explanation:

Initial volume of balloon = 4/3 x  3.14 x (9.905/2)³

=508.56 m³

Final volume of balloon = 4/3 x 3.14 x (16.502/2)³

= 2351.73 m³

Increase in volume = 1843.17 m³

Cross sectional area of inlet  A  = 3.14 x( 1.458/2)²

A = 1.6687 m²

Volume rate of flow of air = cross sectional area x velocity of inflow

= 1 .6687 V [ V is velocity of inflow ]

Total time taken = Increase in volume / rate of flow of air

17.108 X 60 = 1843.17 / 1.6687 V

V = \frac{1843.17}{1.6687\times17.108\times60}

v = 1.076 m /s

8 0
3 years ago
Consider the mixing of 0.8 kg/s of hot water at 348 K and 1 kg/s of cool water at 298 K that is generating warm water. Assume no
Drupady [299]

Answer:

T_warm = 47.22 C

Explanation:

Using energy balance for the system:

m_1*h_1 + m_2*h_2 = m_3*h3   ... Eq1

h_i = c_p. T_i   ... Eq 2

m_1 + m_2 = m_3   ... steady flow system (Eq 3)

Substitute Eq 2 and Eq3 in Eq1

m_3 = 0.8 + 1 = 1.8 kg/s

(0.8)*(4.18)*( 348-273) + (1)*(4.18)*( 298-273) = 1.8 * 4.18 *T_3

T_3 = 355.3 / (1.8*4.18) = 47.22 C

3 0
3 years ago
Bài 3: Cho cơ cấu culít (hình 3.5) với các kích thước động lAB = 0,5lAC = 0,1m. Khâu 3 chịu tác dụng của mô men M3 = 500 N. Cơ c
lesya [120]
??????????????????????
3 0
3 years ago
A water initially contains 40 mg · L−1 of Mg2+. The pH of the water is increased until the concentration of hydroxide ion (OH−)
Darya [45]

Answer:

concentration of Mg ion  = 0.0122 g/L

Explanation:

Given data;

initial concentration of Magnesium in water is 40 mg/l

concentration of (OH^-) = 0.001000

we have dissociation reaction  Magnesium dioxide

Mg(OH)_2 \rightarrow Mg^{2+} +  2OH^{-}

from above reaction we can conclude

concentration of Mg(OH)_2 = \frac{OH}{2} = \frac{.0010}{2} = 0.0005 M

Mass of magnesium ion is calculated as = Mg mole * molar mass of magnesium

concentration of Mg ion = 0.0005*24.305 g/mol = 0.0122 g/L

3 0
4 years ago
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