Answer:
The mass flow rate of jet =69.44 kg/s
Explanation:
Given that
velocity of jet v= 60 m/s
Power P=250 KW
As we know that force offered by water F
Power P= F.v
So now power given as
We know that mass flow rate = ρAv
250 x 1000 = mass flow rate x 3600
mass flow rate = 69.44 kg/s
So the mass flow rate of jet =69.44 kg/s
Answer:
T2 ( final temperature ) = 576.9 K
a) 853.4 kJ/kg
b) 1422.3 kJ / kg
Explanation:
given data :
pressure ( P1 ) = 90 kPa
Temperature ( T1 ) = 30°c + 273 = 303 k
P2 = 450 kPa
Determine final temperature for an Isentropic process
----------- ( 1 )
T2 = 303 = 576.9K
Work done in a piston-cylinder device can be calculated using this formula
------- ( 2 )
where : cv = 3.1156 kJ/kg.k for helium gas
T2 = 576.9K , T1 = 303 K
substitute given values Back to equation 2
= 853.4 kJ/kg
work done in a steady flow compressor can be calculated using this
where : cp ( constant pressure of helium gas ) = 5.1926 kJ/kg.K
T2 = 576.9 k , T1 = 303 K
substitute values back to equation 3
= 1422.3 kJ / kg