We don’t have a model or a photograph to actually represent us the green that is shaded.
Add a photograph and rewrite this question.
I must guess letter B.
Answer:
Function
Please mark me as brainliest.
Answer:
+
*LN(|
|) +C
Step-by-step explanation:
we will have to do a trig sub for this
use x=a*tanθ for sqrt(x^2 +a^2) where a=2
x=2tanθ, dx= 2 sec^2 (θ) dθ
this turns
into integral(sqrt( [2tanθ]^2 +4) * 2sec^2 (θ) )dθ
the sqrt( [2tanθ]^2 +4) will condense into 2sec^2 (θ) after converting tan^2(θ) into sec^2(θ) -1
then it simplifies into integral(4*sec^3 (θ)) dθ
you will need to do integration by parts to work out the integral of sec^3(θ) but it will turn into (1/2)sec(θ)tan(θ) + (1/2) LN(|sec(θ)+tan(θ)|) +C
then you will need to rework your functions of θ back into functions of x
tanθ will resolve back into
(see substitutions) while secθ will resolve into
sec(θ)=
is from its ratio identity of hyp/adj where the hyp. is
and adj is 2 (see tan(θ) ratio)
after resolving back into functions of x, substitute ratios for trig functions:
=
+
*LN(|
|) +C
Answer:

Step-by-step explanation:
Given equation:
![\sqrt[3]{8x^5} - \sqrt[4]{256y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8x%5E5%7D%20-%20%5Csqrt%5B4%5D%7B256y%5E3%7D)
(
!
Answer:
c
Step-by-step explanation: