Answer:
17
Step-by-step explanation:
Number of students in soccer club, n(S) = 50
Number of students in Art club, n(A) = 53
Number of students in Gaming club, n(G)
n(
) = 100
n(
) = 9
n(
) = 20
n(
) = 35
n(
) = 29
Formula:
n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )
Putting the values:
100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9
100 = 112 + n(G) - 84
n(G) = 72
Number of students in gaming club only = n(G) - n(
) - n(
) + n(
)
= 72 - 35 - 29 + 9
= <em>17</em>
Answer:
10/13 = 76.92%
Step-by-step explanation:
The question is missing some information because the underline is missing.
If we make table based on if the letter upper case (A) or lower case(a), and if the letter underlined(B) vs not underlined(b) the data will be:
A a
B 4 3 7
b 3 3 6
total 7 6
There are total of 13 letter there. The calculation will be:
P(A or B) = P(A) + P (B) - P(A and B) = (7 + 7 -4) / 13= 10/13 = 76.92%
Answer:
6
Step-by-step explanation:
5% of 120 were late
=
× 120
= 0.05 × 120
= 6
What I did is to add 0.52
+0.15
then try to find what could equal the same amount with 0.52