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ki77a [65]
3 years ago
6

If one real number is equal to a second real number, and the second real number is equal to a third real number, then the first

real number must equal the third:
If a = b and b = c, then a = c
Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."

Step-by-step explanation: I think this is the problem ur on

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Sabena invests $250 in an account that earns 2.4% interest per year compounded continuously. How many years will it take the acc
g100num [7]

Answer:

It'll take 7.5967 years to have $300 on that account.

Step-by-step explanation:

This problem involves a compounded interest compounded continuously, so in order to solve it we must use the formula for those cases as shown below:

M = C*e^(i*t)

Where M is the final value, C is the initial capital, i is the interest rate and t is the total time. We have:

300 = 250*e^(0.024*t)

e^(0.024*t) = 300/250

e^(0.024*t) = 1.2

0.024*t = ln(1.2)

t = ln(1.2)/0.024 = 7.5967

It'll take 7.5967 years to have $300 on that account.

6 0
3 years ago
**!!PLEASE ANSWER!!**
sammy [17]

Answer:

Answer: 155.12km

Step-by-step explanation:

sin(64˚) x 78 = 70.11 (2DP)

70.12 (2DP) + 85 = 155.1059356 (155.12 - 2DP)

5 0
3 years ago
Linear Programming:
tatuchka [14]
Let the number of large bookcases be x and number of small bookcases be y, then
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The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67

Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
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Andrej [43]
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85,680

Step-by-step explanation:

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