Perimeter of a rectangle:
P=2I+2W=2(I+w)
But if the length and width of a rectangle are both double, then we would have:
Length=2I
width=2w
Therefore, its perimeter would be:
P=2(2I+2w)=4(I+w)
the old perimeter was P=2(I+w) and the new perimeter is P=4(I+w)=2[2(l+w)]
There the perimeter is twice as great.
Answer: C) the perimeter is twice as great.
Answer:
y=5x-13
Step-by-step explanation:
2r-6+5r=3-r+7
7r-6=10-r
7r+r=10+6
8r=16
r=16/8
r=2
0.25 or 1/4 as a fraction
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