Ask question

Ask question

All categories

Ad libitum [116K]

3 years ago

6

Pedro puts $400.00 into an account to use for school expenses. The account earns 4% interest, compounded annually. How much will

be in the account after 5 years? Use the formula A=P1+ r n nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years. Round your answer to the nearest cent.

1 answer:

Nastasia [14]3 years ago

7 0

After 5 years the amount in the account will be $ 487.

<u>Step-by-step explanation:</u>

Compound Interest, A = $P ( 1 + \frac{r}{n})^ {nt}$

Where A denotes the investment's future value

P is the Principal amount = $ 400.00

r is the rate of interest annually in decimals = 0.04

n is the no. of times the interest is compounded per unit time, t = 1

t - the number of years or days or months the amount is invested = 5 years

Now we have to plug in those values in the above formula as,

A = $400 ( 1 + \frac{0.04}{1})^ {1\times 5}$

= 400(1+ 0.04)⁵

= 400(1.04)⁵

= 486.66 ≈ $ 487

You might be interested in

What numbers are divisible by 810

Andrews [41]

If only + numbers are acceptable, then the numbers divisible by 810 are represented by {810n}, where n = {0, 1, 2, 3, ... }

8 0

2 years ago

Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature is 45 degrees at midnig

Paraphin [41]

Answer:

D = 9sin(2π(t + a)/24) + 45

Step-by-step explanation:

Let's find the average temperature;

(54 + 36)/2 = 45°

Amplitude = 54 - 45 = 9

From the wave equation, we can write the temperature as;

D = 9sin(2π(t + a)/24) + 45

Where;

D is the temperature

t is the time in hours after midnight

a is a "phase" that is used to set the time at which temperature(D) occurs

5 0

2 years ago

Is √8 a rational or irrational number

yawa3891 [41]

Answer:

irrational

Step-by-step explanation:

irrational because there will still be a 2 under the root when you simplify to 2√2

3 0

3 years ago

Classify each polynomial and determine its degree. the polynomial 3x2 is a with a degree of . the polynomial x2y 3xy2 1 is a wit

Fofino [41]

$\rm 3x^2$ is the polynomial of one variable with second-order and $x^2y+3xy^2+1$ is the polynomial of two variables with third-order

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.

We have polynomials:

$\rm 3x^2$ and

$x^2y+3xy^2+1$

For $3x^2$

In this polynomial, the number of variables is one and the maximum power of x is 2, therefore:

This is the polynomial of one variable with second order.

In polynomial, $x^2y+3xy^2+1$ there are two variables x and y.

The maximum power of x is 3( x has a power of 2 and y has a power of 1)

This is the polynomial of two variables with third order.

Thus, $\rm 3x^2$ is the polynomial of one variable with second-order and $x^2y+3xy^2+1$ is the polynomial of two variables with third-order.

Learn more about Polynomial here:

brainly.com/question/17822016

7 0

2 years ago

On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is

OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation.

$P(x,y)$ - Original point.

$k$ - Scale factor.

$P'(x,y)$ - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

( $P(x,y) = (10, 40)$ , $Q(x,y) = (70, 120)$ , $O(x,y) = (0,0)$ , $k = 5$ )

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$

$P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]$

$P'(x,y) = (50,200)$

$Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]$

$Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]$

$Q'(x,y) = (350, 600)$

Then, the length of the resulting segment is determined by following Pythagorean identity:

$l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}$

$l_{P'Q'} = 500$

The length of the resulting segment is 500.

3 0

2 years ago