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Ad libitum [116K]
3 years ago
6

Pedro puts $400.00 into an account to use for school expenses. The account earns 4% interest, compounded annually. How much will

be in the account after 5 years? Use the formula A=P1+ r n nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years. Round your answer to the nearest cent.
Mathematics
1 answer:
Nastasia [14]3 years ago
7 0

After 5 years the amount in the account will be $ 487.

<u>Step-by-step explanation:</u>

Compound Interest, A = P ( 1 + \frac{r}{n})^ {nt}

Where A denotes the investment's future value

P is the Principal amount = $ 400.00

r is the rate of interest annually in decimals = 0.04

n is the no. of times the interest is compounded per unit time, t = 1

t - the number of years or days or months the amount is invested = 5 years

Now we have to plug in those values in the above formula as,

A = 400 ( 1 + \frac{0.04}{1})^ {1\times 5}

   = 400(1+ 0.04)⁵

  = 400(1.04)⁵

 = 486.66 ≈ $ 487

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The sum of 3 consecutive integers is 78. What is the integer closest to zero?
vova2212 [387]

Answer:

25

Step-by-step explanation:

Let n be the first integer.

Then the second integer will be (n + 1).

And the third will be (n + 2).

The sum is 78. Therefore:

n+(n+1)+(n+2)+78

Solve for n. Combine like terms:

3n+3=78

So:

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Therefore:

n=25

Therefore, the first integer is 25.

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Please Help extra points
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<h2>A. $123.51</h2><h2 />

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A:

129.4635

129.4625

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C:

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The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
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Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

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Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

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Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

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Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

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It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

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P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

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