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3 years ago

Classify the following reaction according to the five basic reaction types:

Chemistry

1 answer:

joja [24]3 years ago

8 0

Answer:

a. single replacement

Explanation:

Chemical equation:

Cd + H₂SO₄ → CdSO₄ + H₂

In given reaction Cd replace the hydrogen and form cadmium sulfate and hydrogen gas.

Single replacement:

It is the reaction in which one elements replace the other element in compound.

AB + C → AC + B

Other options are incorrect because,

Combustion:

In combustion reaction substances are burn in the presence of oxygen and form carbon dioxide and water.

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

A + B → AB

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

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The ingredient label for a fruit drink reads: water, sugar, orange juice, high fructose corn syrup, vitamin C, sodium benzoate (

Alborosie

Answer:

Explanation:

C is the only one that is true. Because sugar comes before juice in the ingredients listed, there is more of it.

4 0

4 years ago

A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from

sweet-ann [11.9K]

Answer:

$T_i~=163.1$ ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

Initial temperature of gold= Unknow

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the heat equation:

$Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT$

$Q_A_u=m_A_u*Cp_A_u*deltaT$

We can relate these equations if we take into account that all heat of gold is transfer to the water, so:

$m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT$

Now we can put the values into the equation:

$60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)$

Now we can solve for the initial temperature of gold, so:

$T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20$

$T_i~=163.1$ ºC

I hope it helps!

5 0

3 years ago

Given the reaction: Mg(s) + 2 AgNO3(aq) → Mg(NO3)2(aq) + 2 Ag(s) Which type of reaction is represented?

Papessa [141]

Mg(s) + 2 AgNO₃(aq) = Mg(NO₃)₂(aq) + 2 Ag(s)

reaction is : single replacement

hope this helps!

6 0

4 years ago

What volume of 12 M HCl solution is needed to make 2.5 L of 1.0 M HCI?

Jlenok [28]

Answer:

0.21 L of 12 M HCL

Explanation:

CV=CV

(12)(x)=(1.0)(2.5)

x=0.21

8 0

4 years ago

Dwayne filled a small balloon with air at 298.5 K. He put the balloon into a bucket of water, and the water level in the bucket

Tcecarenko [31]

Answer : The volume of the balloon will be, 0.494 liters

Solution :

Charles' Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

or,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1$ = initial volume of gas = ?

$V_2$ = final volume of gas = 0.54 L

$T_1$ = initial temperature of gas = 273.15 K

$T_2$ = final temperature of gas = 298.5 K

Now put all the given values in the above equation, we get the initial volume of balloon.

$\frac{V_1}{273.15K}=\frac{0.54L}{298.5K}$

$V_1=0.494L$

Therefore, the volume of the balloon will be, 0.494 liters

5 0

3 years ago

Read 2 more answers