The discriminant can be found using the formula b^2-4ac
First put your equation in standard form, where all your values are on one side, and just add f(x) or y in front of your equation.
y= 8p^2-8p+2
The first value of your equation is a (a=8)
The second term of your equation is b (b=-8)
The last term of your equation is c (c=2)
Plug in the values to the discriminant equation b^2-4ac
Answer:
The simplest way to teach middle school math scale drawings is to use real pictures to relate to each other to explain the concept. For example, scaling a red ball of 1" to a ball of 2" and so on. This will show how the ball increases by size by adding 1" each time.
We conclude that after 50 days, there will be 67 lily pads.
<h3>how many will there be after 50 days?</h3>
We know that the number increases by 25% every 10 days.
In 50 days we have 5 groups of 10 days, so there will be five increases of 25%.
We know that the initial number is 22 lily pads, if we apply five consecutive increases of the 25% we get:
N = 22*(1 + 25%/100)*...*(1 + 25%/100%)
( the factor (1 + 25%/100%) appears five times)
So we can rewrite:
N = 22*(1 + 25%/100%)⁵
N = 22*(1 + 0.25)⁵ = 67.1
Which can be rounded to the nearest whole number, which is 67.
So we conclude that after 50 days, there will be 67 lily pads.
If you want to learn more about percentages:
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To find the z-score for a weight of 196 oz., use
![z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B196-180%7D%7B8%7D%3D%5Cfrac%7B16%7D%7B8%7D%3D2)
A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.