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docker41 [41]
2 years ago
8

In the base-ten number system, ten digits {0, 1, 2, 3, 4, 5, 7, 8, 9) are used for number

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
6 0

Answer:

..............I think its wrong .......

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PLEASE HELP I BEG YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
ruslelena [56]

Answer:

R1:   Given

R2:   Subtraction Property of Equality

R3:   Distribute Property

R4:   Addition Property of Equality

R5:   Division Property of Equality

Write a paragraph proof for the following conjecture: m∠1 + m∠2 = m∠4

Prove: m∠3 + m∠1 + m∠2 = 180°

Given: ∠1 + ∠2 = ∠ 4

∠4 + ∠3 must be 180° because they are supplementary

If ∠4 + ∠3 is 180, and ∠1 + ∠2 = ∠4, you can substitute ∠4 in the first equation for ∠1 + ∠2.

Hence, we arrive at the answer ∠1 + ∠2 + ∠3 = 180.

Plz mark brainliest:)

7 0
3 years ago
PLEASE HELP!!!
storchak [24]
1. 7.00
2. A. <span>Sarah is paying the smaller price of $1.25 per cupcake. 

</span>
6 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
if p(x) = x+ 7/ x-1 and q (x) = x^2 + x - 2, what is the product of p(3) and q(2)? a. 50 b. 45 c. 40 d. 20 e. 6
Amanda [17]

Answer:

d. 20

Step-by-step explanation:

To answer the question given, we will follow the steps below:

we need to first find p(3)

p(x) = x+ 7/ x-1

we will replace all x by 3 in the equation above

p(3) = 3+7 / 3-1

p(3) = 10/2

p(3) = 5

Similarly to find q(2)

q (x) = x^2 + x - 2,

we will replace x by 2 in the equation above

q (2) = 2^2 + 2 - 2

q (2) = 4 + 0

q (2) = 4

The product of p(3) and q(2)   =   5 × 4   = 20

6 0
2 years ago
In a fifth-grade class, 3/4 of the students like to go to the movies. Of the students who like to go to the movies, 2/3 of them
Ksju [112]
Students who like action movies: 3/4 x 2/3 = 1/2 of the fifth grade class students

Students who like comedies: 1/2 x 4/5 = 2/5 of the fifth grade class students
4 0
2 years ago
Read 2 more answers
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