All categories

3 years ago

How could Mendeleev predict the properties of elements that had not yet been discovered?

Chemistry

1 answer:

icang [17]3 years ago

3 0

It was the element of aluminium where they predict their properties <span />

You might be interested in

The Law of Conservation of Energy states that Energy cannot be ____________ nor _____________ but only change from one _________

Yakvenalex [24]

3. Created, destroyed, form Is the correct answer

3 0

3 years ago

An aqueous solution containing 17.5 g of an unknown molecular compound in 100.g water was found to have a freezing point of-1.8°

Zigmanuir [339]

Answer:

The answer to your question is 178.6 g

Explanation:

Data

ΔT = 1.8 °C

mass = 17.5 g

mass of water = 100 g

Kc = 1.86

Process

1.- Calculate the molality using the following formula

ΔTc = mKc

solve for m

m = ΔTc/Kc

substitution

m = 1.8/1.86

result

m = 0.968

2.- Calculate the number of moles

m = # of moles/kg of solvent

kg of solvent = 0.1 kg

# of moles = m x kg of solvent

# of moles = 0.968 x 0.1

# of moles = 0.0968

3.- Calculate the molar mass

x g molar mass --------------------- 1 mol

17.5 g --------------------- 0.0968 moles

x = (1 x 17.5)/0.0968

x = 178.6 g

4 0

3 years ago

What mass of magnisium bromide is formed when 1.00 g of Mg + br

ella [17]

Mass of Magnesium bromide : 5.76 g

<h3>Further explanation</h3>

Complete question

<em>What mass of Magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?</em>

<em />

Reaction

<em /> $\tt Mg+Br_2\rightarrow MgBr_2$ <em />

mol Mg

$\tt \dfrac{1}{24}=0.042$

mol Br₂

$\tt \dfrac{5}{160}=0.0313$

Limiting reactants : Br₂(smaller)

mol MgBr₂ = mol Br₂=0.0313

mass MgBr₂ :

$\tt 0.0313\times 184,113 =5.76~g$

5 0

3 years ago

In a recent Grand Prix, the winner completed the race with an average speed of 299.8 km/h. What was his speed in miles per hour,

scoundrel [369]

Answer :

(a) The speed is, 186.287 mi/hr

(b) The speed is, 83.277 m/s

(c) The speed is, 273.22 feet/s

Explanation :

(a) We are given the speed is, $299.8km/hr$

As we know that,

$1km=\frac{1}{1.60934}mi$

By using both the conversion, we get:

$299.8km/hr$

$\Rightarrow \frac{299.8km}{1hr}\times \frac{1mi}{1.60934km}$

$\Rightarrow 186.287mi/hr$

The speed is, 186.287 mi/hr

(b) We are given the speed is, $299.8km/hr$

As we know that,

$1km=1000m$

and,

$1hr=3600s$

By using both the conversion, we get:

$299.8km/hr$

$\Rightarrow \frac{299.8km}{1hr}\times \frac{1000m}{1km}\times \frac{1hr}{3600s}$

$\Rightarrow 83.277m/s$

The speed is, 83.277 m/s

(c) We are given the speed is, $299.8km/hr$

As we know that,

$1km=3280.84feet$

and,

$1hr=3600s$

By using both the conversion, we get:

$299.8km/hr$

$\Rightarrow \frac{299.8km}{1hr}\times \frac{3280.84feet}{1km}\times \frac{1hr}{3600s}$

$\Rightarrow 273.22feet/s$

The speed is, 273.22 feet/s

3 0

4 years ago

Two skydivers jump out of a plane. As the skydivers are in free fall, the potential energy they possessed at the airplane door I

LiRa [457]

That is true, the potential energy they possessed at the airplane door would be converted to kinetic energy. And if they driver is high up, he has further to fall. As the skydivers jump, the energy would be converted to kinetic energy.

7 0

4 years ago

Read 2 more answers