<h3>
Answer: Choice C</h3>
Explanation:
In this answer choice, we effectively have two columns. In the first column is simply R and B, with R over B. This represents spinning either red (R) or blue (B).
Depending on the outcome, you branch the same outcomes from that.
So if you spin R, then you'll have R and B branch off that. Same idea applies to blue as well.
Something like choice D doesn't work because we have R show up twice at the very bottom.
Did the question give you any lengths of the sides?
Answer:
1.5 lbs b/c 2 block equal 3 vs 3 blocks equal 3
Step-by-step explanation:
Answer: See explanation
Step-by-step explanation:
Here is the complete question:
A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.
A. Students: 72
Minimum of chaperones: 9
B. Students: 16
Minimum of chaperones: 2
C. Students: 60
Minimum of chaperones: 6
D. Students: 45
Minimum of chaperones: 5
E. Students: 40
Minimum of chaperones: 8
Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.
We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:
Students: 72
Minimum of chaperones: 9
This will be: 72/9 = 8
Therefore, this is correct.
B. Students: 16
Minimum of chaperones: 2
This will be: 16/2 = 8
This is correct
C. Students: 60
Minimum of chaperones: 6
This will be: = 60/6 = 10.
Therefore, this is wrong
D. Students: 45
Minimum of chaperones: 5
This will be 45/5 = 9
Therefore, this is wrong.
E. Students: 40
Minimum of chaperones: 8
This will be: 40/5 = 8.
Therefore, this is wrong.
Therefore, options A and B are correct.
Answer:
The number is 86
Step-by-step explanation:
Let the number be 
, then the reverse is 
The sum of the reversed number and the original number is 154,
We simplify this to get:
....eqn(1)
If the ones digit in it is 2 less than the tens digit, then
....eqn(2)
Putt equation (2) in (1)
Put x=8 in the second equation:
The original number is 86
