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katovenus [111]
3 years ago
15

Please help i am stuck

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Explanation:

All of these are done the same way.

1. Set your compass to a distance slightly longer than the distance from the point to the line you want the perpendicular to.

2. Using the point as a center, draw an arc that intersects the line in 2 places. Consider those points to be "P" and "Q".

3. You can leave the compass as is, or set it to any other distance longer than half the distance between P and Q. Using this radius, and using P and Q as centers, draw intersecting arcs on the other side of the line from the original point. Consider the intersection of those arcs to be point "R".

4. A line through the original point and point R will be perpendicular to the line, as you want.

_____

In problem 1, the point and line are obvious.

In problem 2, the point is the vertex opposite the line of interest. (There will be 3 similar constructions.)

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formula is A=P(1-\frac{r}{n})^{nt}

where A=final amount

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r=interest rate in decimal

n=number of times per year it is compounded

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also that (a^b)^c=a^{bc}

2(5745)=5745(1+\frac{0.065}{12})^{12t}, solving for t

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2=(1+\frac{0.065}{12})^{12t} I'd rather not simplify this because it give us a decimals and those aren't exact, if we combine, we get 12.065/12 for inside parenthases

2=(\frac{12.065}{12})^{12t}

take ln of both sides

ln(2)=ln((\frac{12.065}{12})^{12t})

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divide both sides by 12ln(\frac{12.065}{12})

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