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katovenus [111]
2 years ago
15

Please help i am stuck

Mathematics
1 answer:
balu736 [363]2 years ago
6 0

Explanation:

All of these are done the same way.

1. Set your compass to a distance slightly longer than the distance from the point to the line you want the perpendicular to.

2. Using the point as a center, draw an arc that intersects the line in 2 places. Consider those points to be "P" and "Q".

3. You can leave the compass as is, or set it to any other distance longer than half the distance between P and Q. Using this radius, and using P and Q as centers, draw intersecting arcs on the other side of the line from the original point. Consider the intersection of those arcs to be point "R".

4. A line through the original point and point R will be perpendicular to the line, as you want.

_____

In problem 1, the point and line are obvious.

In problem 2, the point is the vertex opposite the line of interest. (There will be 3 similar constructions.)

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Alborosie
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Hope my answer helped u :)
7 0
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Read 2 more answers
Triangle ABC is an isosceles triangle. Angles B and C are base angles, with measurements of (11x −10)° and (7x + 10)°, respectiv
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Answer:

m∠A = 90°

Step-by-step explanation:

In isosceles triangle base angles are congruent. That means we can equate measurments of angle B and angle C and solve for x!

m∠B = m∠C

11x - 10 = 7x + 10

4x - 10 = 10

4x = 20

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Now let's insert x back in the expressions for angles.

m∠B = (11x − 10)° = (11(5) − 10)° = 45°

m∠C = (7x + 10)° = (7(5) + 10)° = 45°

<u>Sum of all angles in the triangle is 180°.</u> Let's make an equation.

m∠A + m∠B + m∠C = 180°

m∠A + 45°+ 45° = 180°

m∠A  = 90°

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1 year ago
What is the domain of this function?
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