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IRISSAK [1]
3 years ago
6

Which element has the highest standard reduction potential? fluorine hydrogen lead lithium

Chemistry
2 answers:
Stolb23 [73]3 years ago
3 0
I think the correct answer from the choices listed above is the first option. The element that has the highest standard reduction potential would be fluorine. Hope this answers the question. Have a nice day. Feel free to ask more questions.
astra-53 [7]3 years ago
3 0

Answer:

A.flourine for plato users

Explanation:#platolivesmatter

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Attempt 3 An irregular lump of an unknown metal has a measured density of 5.50 g/mL. The metal is heated to a temperature of 153
shepuryov [24]

Answer:

i think it's 20.0mL

Explanation:

i learned this question in class

4 0
3 years ago
HELPPPPP ME <br><br>PLISSSSS ​
Talja [164]

Answer:

pH value of a solution depends on the concentration of hydrogen ions

(pH = -log[H+(aq)].

Hydrochloric acid is a strong acid, while ethanoic acid is a weak acid. Strong acids ionize completely in water (to give ions which includes H+(aq)), while weak acids only ionize partially in water.  

Therefore, even if both hydrochloric acid and ethanoic acid are monobasic acids (each molecule can ionize completely to give 1 hydrogen ion), since hydrochloric acid ionizes completely in water and ethanoic acid does not ionize completely, the concentration of hydrogen ions in hydrochloric acid is higher than that of ethanoic acid, leading to a lower pH value for hydrochloric acid, while higher for ethanoic acid.

8 0
3 years ago
What is the volume of a solid with a mass of 17.4 g and a density of 0.934 g /cm cubed?
Anvisha [2.4K]

Answer:

18.6 g/cm^3

Explanation:

17.4g/0.934g/cm^3

(divide)

5 0
3 years ago
Bananas Foster is an example of a dessert that is flambéed. A Bananas Foster label states the accepted number of Calories to be
WINSTONCH [101]

Answer:

6.00%

Explanation:

Step 1: Given data

Accepted value for the number of calories in a Bananas Foster: 300 calories

Measured value for the number of calories in a Bananas Foster: 318 calories

Step 2: Calculate the percent error in the measure

We will use the following expression.

%error = |accepted value - experimental value|/ accepted value × 100%

%error = |300 cal - 318 cal|/ 300 cal × 100% = 6.00%

4 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
gladu [14]
Hbro  dissociate  as  follows
HBro--->  H+  +  BrO-
  Ka=  (H+)(BrO-)  /  HBro
 PH  =  -log (H+)
therefore (H+)  =  10^-4.48= 3.31  x10^-5
ka is  therefore= ( 3.31  x 10^-5)^2/0.55=1.99  x10^-9
6 0
3 years ago
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