Here's one shortcut:
2.3×10^9=1000(2.3×10^6) because your adding 3 more zeros to 2300000
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
Step-by-step explanation:
Note that 128 = 64*2. The square root of 128 is thus 8sqrt(2). Answer B is the only one that could be correct.
Answer:
y= -3x + 8
Step-by-step explanation:
Put -2x + 6y = -4 into slope-interceltp form
Take the negative reciprocal of the slope.
Use this reciprocal in point-slope form
and you have,
= y= -3x + 8
<em>(EDITED)</em> Steps:
2x+6y = -4
6y=2x - 4
y= 1/3x + 2/3
if two lines are perpendicular,
m1 * m2 + -1
1/3 * m2 = -1
m2 = -3
the line perpendicular to this line is
y = -3x + k ; k ∈ R
the line passes through the point (5,-7)
so,
-7 = -3. (5) +k
-7 = -15 + k
k = 8
∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is
y= -3x + 8
Hope this helps, have a nice day/night! :D
Step-by-step explanation:
Given the equation:
y = 0.09x where:
- x: represents the cost of the item before tax is added.
- y: represents the amount of sales
=> On a coordinate plane, the x-axis is labeled Cost of Item (in dollars) and the y-axis is labeled sales tax (in dollars)
We create a table of values
x y
0 0
10 0.9
=> the line go through two points (0, 0) and (10, 0.9)
Hence tow dwaw a graph, we just connect two points together.
Please have a look at the attached photo.
