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andrew11 [14]
2 years ago
6

Find the trignometric ratios of theta.also find trignometric ratio of beta Please solve it​

Mathematics
1 answer:
eimsori [14]2 years ago
5 0

Answer:

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The quotient of twenty-nine and a number h
satela [25.4K]

Answer:

29/h

Step-by-step explanation:

quotient is the result of division so you divide 29 by h which gives you 29/h or h/29

4 0
2 years ago
A sheet of paper is 8.5 in X 11 inches if you cut 2 in squared from each corner what is the area if the paper
IceJOKER [234]
A=length x height. First we want to know the area of the original sheet of paper. 8.5 x 11= 93.5 inches squared. Then we take two squares with side length 2 inches. The area of each of these squares is 2 x 2, or 4 inches. Since there are two, the total area we take away is 8 inches. We subtract 8 inches from 93.5 since we took it away, and the final area of the paper is 85.5 inches^{2}

Hope this helped!
3 0
2 years ago
Write a number with the digit 8 in the tens place
sladkih [1.3K]
280
The 0 is in the ones.
The 8 is in the tens.
The 2 is in the hundreds.
8 0
2 years ago
Read 2 more answers
PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!
Harrizon [31]
180-53 is 127 angle 6 and 3 would be the same so your answer is 127
3 0
2 years ago
2 Here are two equations:
MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

6(3) + 4(4) = 34\\18+16=34\\34=34\\

Putting in Equation 2:

5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15

<u>ii. (4,2.5)</u>

Putting in Equation 1:

6(4) + 4(2.5) = 34\\24+10=34\\34=34\\

Putting in Equation 2:

5(4) - 2(2.5) = 15\\20-5 = 15\\15=15

<u>ill. (5,5)</u>

6(5) + 4(5) = 34\\30+20=34\\50\neq 34

Putting in Equation 2:

5(5) - 2(5) = 15\\25-10 = 15\\15=15

<u>iv. (3,2)</u>

6(3) + 4(2) = 34\\18+8=34\\26\neq 34

Putting in Equation 2:

5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

  • brainly.com/question/10534381
  • brainly.com/question/10538663

#LearnwithBrainly

8 0
3 years ago
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