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andrew11 [14]
3 years ago
6

Find the trignometric ratios of theta.also find trignometric ratio of beta Please solve it​

Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

{\boxed{ \fbox{ \fbox{ \fbox{ \red{hello}}}}}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{green}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{blue}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{red}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{gray}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

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4. 150 men working in a factory produce 6000 articles in 15 working days. How long will it take, a. 50 men to produce the 6000 a
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<h2><u><em>Answer:</em></u></h2><h2><u><em></em></u></h2><h2><u><em>work done by 150 men on 1 day=6000/15.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>work done by 1 man on 1 day=6000/(15*150).</em></u></h2><h2><u><em></em></u></h2><h2><u><em>work done by 50 men on 1 day=(6000*50)/(15*150).</em></u></h2><h2><u><em></em></u></h2><h2><u><em>let X days taken to produce 6000 articles by them, then</em></u></h2><h2><u><em></em></u></h2><h2><u><em>((6000*50)/(15*150))X=6000.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>on solving X=45 days.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>So 45 days will take for 50 men to produce 6000 articles.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Please mark me Brainliest</em></u></h2>
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3 years ago
22 + 14x = 14x + 22 <br> Is this Commutative, Distributive, or Associative
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Answer:

I think the answer is Associative.

Step-by-step explanation:

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Lynn is trying to determine how far away Student B is from the balloon. He decides to use the
kaheart [24]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as the image that illustrates the scenario is not given.</em>

<em>However, I can deduce that the question is about a right-angled triangle.</em>

<em>So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.</em>

<em />

<u>For triangle A (solve for b)</u>

Using cosine formula.

\cos \theta = \frac{Adjacent}{Hypotenuse}

\cos 60= \frac{5}{b}

Make b the subject

b= \frac{5}{\cos 60}

<u>For triangle B (solve for b)</u>

Using cosine formula.

\sin \theta = \frac{Opposite}{Hypotenuse}

\sin 60= \frac{b}{5}

Make b the subject

b = 5\sin 60

<u>For triangle C (solve for b)</u>

Using cosine formula.

\tan \theta = \frac{Opposite}{Adjacent}

\tan 60= \frac{b}{5}

Make b the subject

b = 5\tan 60

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How many times can six go into 25 with a full number​
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Answer:

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i just know

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