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forsale [732]
2 years ago
7

How do amphibians breathe on land and in water​

Biology
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

Answer:

Most amphibians can breathe both through cutaneous respiration (through their skin) and buccal pumping - though some also retain gills as adults. Some aquatic salamanders (and all tadpoles) have gills and can breathe underwater thanks to them. The Mexican axolotl, for example, never loses its gills.

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2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

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How are bacteria classified?
Cerrena [4.2K]

bacteria are classified into 5 groups, spherical (cocci), rod (bacilli), spiral (spirilla), comma (vibrios) or corkscrew (spirochaetes).

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AUGGCGUUU which of the following DNA strands could have been the template for this RNA?
Delvig [45]

Answer:

3' TACCGCAAA 5'

Explanation:

Transcription is the process by which a particular DNA sequence (e.g., a gene) is used as a template to synthesize a complementary RNA sequence that grows in a 5′ → 3′ direction. This RNA molecule is usually a messenger RNA (mRNA) which is then used to synthesize a polypeptide chain (i.e., a protein) by a process called translation. The complementary RNA molecule produced during transcription is synthesized according to the base pair rules, i.e., Adenine (A) bases always pair with Thymine (T) bases, while Guanine (G) bases always pairs with Cytosine (C) bases. In RNA, Uracil (U) bases pair with adenine, thereby replacing thymines during transcription.

7 0
2 years ago
Explain what is meant by the term differentiate.
bulgar [2K]

The process by which cell types or cell populations attain distinct and different forms and functions is called differentiation.

This is the process that allows the stem cells to differentiate and form a cell type that will perform a specific function.

The process of differentiation is essential for the formation of the different organs in multicellular organisms.

3 0
2 years ago
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Compare and contrast point mutations and chromosomal mutations. Which part of the organism's DNA is affected as a result of each
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Answer:

In point mutation,the gene is affected however in chromosomal mutations,there is change in the structure or number of the chromosomes

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3 years ago
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