The rate at which a radioactive isotope<span> decays is measured in </span>half-life. The termhalf-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a radioactive material to disintegrate. </span>Half-lives<span> for various </span>radioisotopes<span> can range from a few microseconds to billions of years.</span>
Answer:
A ) 
b) There are approximately 100,000,000 atoms on the 1.32 cm lines
Explanation:
To ensure the accuracy of our answer, we will have to make sure we work in the appropriate units.
A
To convert
to inches, we can use this factor.
1 m = 39.3701 inches
Therefore
=
B
To find the number of atoms on a 1.32 cm line, we will first of all need to convert 1.32 cm to meters.
1.32 cm = 0.0132 metres (divided 1.32 by 100 to convert to metres)
Assuming all the atoms are arranged side by side, with their edges touching on the 0.0132m line, the number of atoms present will be
= 100,000,000 atoms
Answer:
Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.
Explanation:
The solar energy cycle functions in the following form:
- Considering that 100% of energy is directed at earth.
- When 100% light is incident on the Earth's surface about 6-7% of it is reflected back by the atmosphere into space.
- 20% is reflected back by the clouds.
- And about 4% is reflected back by Earth's surface.
- 16% of solar energy is absorbed by the atmosphere, 3% is absorbed by clouds and 51% is absorbed by land and ocean.
- From the absorbed energy, 64% is radiated back to space from clouds and atmosphere and 6% is directly radiated back to space from earth.
- From the radiated energy 15% is absorbed by the atmosphere and 23% is carried by the clouds and atmosphere through the latent heat in water vapor.
Therefore, absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.
Learn more about solar energy here:
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Answer:
0.026 V
Explanation:
Given that,
Inductance of the coil, L = 6 mH
The current changes from 0.2 A to 1.5 A in a time interval of 0.3 s
We need to find the magnitude of the average induced emf in the coil during this time interval. The formula for the induced emf is given by :

So, the magnitude of induced emf is 0.026 volts.
You do it by the pressure difference it causes in the medium. Even in transversal waves, you usually need different units than meters because the wave has electric and magnetic vectors and not really any height to speak of.
you measure the amount of excursion from the equilibrium (no wave) level of whatever parameter is fluctuating.