1. Which of the following is not included

2. How are electromagnets different from other magnets?

Stella [2.4K]

A magnet is made from materials that is magnetized and create its own persistent magnetic field while a electromagnet is mad from coil of wire which acts as a magnet when electric current passes through it.

4 0

3 years ago

g The electric field in a sinusoidal wave changes as E =125 N>C2cos 311.2 * 1011 rad>s2t +14.2 * 102 rad>m2x] (a) In wh

Elan Coil [88]

Answer:

a) the propagation direction is x, b) E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d) f = 4.95 10¹¹ Hz, e) λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

C = E / B

B = E / c

B = 125/3 10⁸

B = 41.67 10⁻⁸ T

d) the angular velocity is

w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

w = 2π f

f = w / 2π

f = 311.2 10¹¹ / 2π

f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

k = 2π /λ

k = 14.2 10² rad / m

λ = 2π / k

λ = 2π / 14.2 10²

λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

4 0

3 years ago

A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.

FinnZ [79.3K]

We have that the maximum height reached by the basketball from its release point is

$S=1.3m$

From the question we are told

A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.
What is the maximum height reached by the basketball from its release point?

Generally the Newtons equation for Motion is mathematically given as

$V^2=u^2+2as\\\\Therefore\\\\0=25-19.6*S\\\\S=\frac{25}{19.6}\\\\S=1.276$

$S=1.3m$

Therefore

The maximum height reached by the basketball from its release point is

$S=1.3m$

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