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Lera25 [3.4K]
3 years ago
7

complete the word equations below to show how the metals are extracted from their oxides: 1) tin oxide + carbon ---> ........

.? + .......? 2) lead oxide + carbon ----> ......? + ......?
Chemistry
1 answer:
boyakko [2]3 years ago
7 0

Answer:

1.) Tin oxide + Carbon → Tin + Carbon monoxide.

2.) Lead oxide + Carbon → Lead + Carbon monoxide.

These equations show that the metals are being extracted by their oxides by heating with carbon. This is because the metals (Tin and Lead) are less reactive than carbon. Remember, extraction methods of metals are determined by their reactivity. Since the elements tin and lead are less reactive than carbon, the extraction process of heating with carbon is needed.  Remember that when a metal heats with carbon, the carbon displaces the metal from the compound and removes the oxygen from the oxide. Leaving you with the metal and carbon monoxide.

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Explanation:

As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.

Hence, calculate the molecular weight of the mixture as follows.

             Weight = 0.09 \times 16.04 + 0.91 \times 29

                          = 27.8336 g/mol

And, molar flow rate of air and mixture is calculated as follows.

                    \frac{800}{27.8336}

                     = 28.74 kmol/hr

Now, applying component balance as follows.

                0.09 \times 28.74 + 0 \times F_{B} = 0.06F_{p}

                   F_{p} = 43.11 kmol/hr

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             Molecular weight of product stream = Mol. weight \times 43.11 kmol/hr

                                  = 0.06 \times 16.04 + 0.94 \times 29

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Hence, mole of O_{2} into the product stream is as follows.

                    0.21 \times 0.94 \times 43.11

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                 \frac{272.31}{1216.67} \times 100

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Thus, we can conclude that the required flow rate of B is 272.31 kg/hr and the percent by mass of O_{2} in the product gas is 22.38%.

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