Answer:
The point-slope equation of the line is y - 2 = 3(x + 9)
Step-by-step explanation:
The form of the point-slope equation is y - y1 = m(x - x1), where
- m is the slope of the line
- (x1, y1) is a point on the line
∵ The slope of a line is 3
∴ m = 3
∵ The line passes through point (-9, 2)
∵ x1 = -9
∴ y1 = 2
→ Substitute the values of m, x1, and y1 in the point-slope form
∵ y - y1 = m(x - x1)
∴ y - 2 = 3(x - (-9))
→ Remember (-)(-) = (+)
∴ y - 2 = 3(x + 9)
∴ The point-slope equation of the line is y - 2 = 3(x + 9)
<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔
units
Therefore the perpendicular distance from B to AC is =
Two angles are supplementary if their measures sum 180°.
Linear angle pairs are adjacent angles (they are together) and they form a straight angle, which is 180°. Therefore, they are supplementary.
But two angles may be separated and yet add 180°, then they are supplementary but are not linear angle pairs.
fomular you say :speed =distance taveled divide by time traveled .......hope this will help
Okie so I can see you tomorrow and I’ll be right there on time to meet
