Answers:
1. A person with 1 exemption making between $580 and $600 would have $<u>21.97</u> withheld.
2. A person with 3 exemptions making between $340 and $360 would have $<u>4.51</u> withheld.
3. A person with 4 exemptions making $610 would have $<u>16.31</u> withheld.
4. A person with 2 exemptions making between $440 and $460 would have $<u>12.16</u> withheld.
5. Tim Worker had $7.84 withheld. What was his wage range? <u>$360-$380</u>
Please, see the attached files.
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The probability that there exist 60 or more defected children is
Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence
Step-by-step explanation:
From the question we are told that
in every 1000 children a particular genetic defect occurs to 1
The number of sample selected is
The probability of observing the defect is mathematically evaluated as
The probability of not observing the defect is mathematically evaluated as
The mean of this probability is mathematically represented as
Substituting values
The standard deviation of this probability is mathematically represented as
Substituting values
the probability of detecting defects can be represented in as normal distribution like
in standardizing the normal distribution the normal area used to approximate is the right of 59.5 instead of 60 because x= 60 is part of the observation
The z -score is obtained mathematically as
The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve
Note: We are looking for the area to the right i.e 60 or more
The total area under the curve is 1
So
