There are 30 days in June and only three of those days are multiples of 8 so you have the probability of 3 out of 30.
Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Answer:
c. x21 + x22 + x23 less or equal than 2800 y2
Step-by-step explanation:
The plant has a maximum capacity of 2800 then the sum of all these operations must be equal to or less than 2800. The site of the plant has capacity constraint which needs to be determine through equation. The total capacity for the plant 2 is only 2800 the operation has to be distributed with keeping in mind the capacity limit.
Answer:40c^2-46c -14
Step-by-step explanation:
(8c+2)*(5c-7)
8c*(5c-7)+2(5c-7)
40c^2-56c+10c-14
40c^2-46c-14
Answer:
C. (5, -3)
Step-by-step explanation:
4x + 3y = 11
x - y = 8 (multiply by 3) --> 3x - 3y = 24
4x + 3y = 11
3x - 3y = 24
---------------------add
7x = 35
x = 5
5 - y = 8
y = 5 - 8
y = -3
(5, -3)
