Answer:
33.94 cms of ribbon
Step-by-step explanation:
Because you need two diagonals to form the x, therefore the amount of ribbon needed is the sum of the distance of both diagonals.
When crossing the diagonal, a rectangular angle is formed, where the diagonal would be the hypotenuse, we know that the distance of the hypotenuse can be calculated by means of the legs, which we know its value (12):
d ^ 2 = a ^ 2 + b ^ 2
a = b = 12
d ^ 2 = 12 ^ 2 + 12 ^ 2
d ^ 2 = 288
d = 288 ^ (1/2)
d = 16.97
16.97 cm is what it measures, a diagonal, therefore tape is needed:
16.97 * 2 = 33.94
A total of 33.94 cms of ribbon is needed
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.
Indeed, those two numbers are relatively prime.
About 5 books have been signed out, so they still have 4.
The answer to this problem= 0
⇒6x + 2 + - 1 - 4x - 3 + - 2x + 2 = 0
⇒2 - 1 - 3 + 2 + 6x + -4x - 2x = 0
⇒1 - 3 + 2 + 6x + -4x - 2x = 0
⇒-2 + 2 + 6x + -4x + -2x = 0
⇒0 + 6x + -4x + -2x = 0
⇒6x - 4x - 2x = 0
⇒2x + -2x = 0
Combine like terms: 2x + -2x = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.
Problem-solving is the definition of the problem. Identify the cause of the problem. Identify, prioritize, and select alternative solutions. and solution implementation. problem-solving process. Troubleshooting resources.
The definition of a problem is something that needs to be resolved or an unpleasant or undesirable condition that needs to be corrected. An example problem is an algebraic equation. An example problem is when it's raining and you don't have an umbrella.
Learn more about the problem here: brainly.com/question/1781657
#SPJ1
9514 1404 393
Answer:
In step 4, Jim's answer is incorrect.
Step-by-step explanation:
In step 1, Jim swaps the order of addends using the commutative property of addition.
In step 2, Jim uses the distributive property to factor -1 from the final two terms. (The associative property lets Jim move parentheses.)
6.1 +(-8.5 -1.3) . . . associative property
6.1 +(-1)(8.5 +1.3) . . . distributive property
In step 3, Jim has used the properties of real numbers to form the sum of two of them.
In step 4, Jim wrote an answer of 1.1, when the answer should have been -3.7. Jim's answer is incorrect.
__
The descriptive statements about steps 2 and 4 are both true.
