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krek1111 [17]
3 years ago
7

What's the best first step in solving-4 + 2/5 > 5/10

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

B

Step-by-step explanation:

There are 2 operations happening on the left side to x.

1. x is being multiplied by -4.

2. 2/5 is being added to -4x.

If you had a number for x, and you wanted to evaluate the left side, first, you would multiply the value of x by -4. Then you would add 2/5.

To solve an equation or an inequality, you do the opposite operation in the opposite order.

Since the second operation was add 2/5, to solve, you start by doing the opposite of the second operation. That means you subtract 2/5 from both sides.

Answer: B

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A2-20-3b= quick answer please using pemdas
Andrew [12]
Pretty sure the answer is -ab-20
7 0
4 years ago
Solve the compound inequality.<br> 5 &lt; 2x - 1 &lt; 9<br><br> Show your work
ASHA 777 [7]

Answer:

3<x<5

Step-by-step explanation:

5<2x-1<9

Add 1 on all the sides because of the inverse operation.

Which is 6<2x<10

The divide 2 on all sides to isolate x.

Which is 3<x<5.

4 0
3 years ago
A ____ is a pair of equal ratios.
12345 [234]
A proportion is a pair of equal ratios.
6 0
3 years ago
A regular six-sided die is rolled 1000 times. Use the binomial distribution to determine the standard deviation for the number o
ANTONII [103]

The standard deviation for the number of times an odd number is rolled is 15.8

<h3>How to determine the standard deviation?</h3>

The given parameters are:

Die = regular six-sided die

n = 1000

The probability of rolling an odd number is:

p = 1/2 = 0.5

The standard deviation is then calculated as;

\sigma = \sqrt{np(1 - p)

This gives

\sigma = \sqrt{1000 * 0.5 * (1 - 0.5)

Evaluate the products

\sigma = \sqrt{250

Evaluate the root

\sigma = 15.8

Hence, the standard deviation is 15.8

Read more about standard deviation at:

brainly.com/question/16555520

#SPJ1

8 0
2 years ago
PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
3 years ago
Read 2 more answers
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