1 m = 0,001 km
1m³ = 0,000000001 km³
278 m³ = 0,000000278 km³ = 2,78×10^(-7) km³
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To answer this question, you need to know the equation for the reaction. The equation should look like this:
<span>2K3PO4 (aq) + 3NiCl2 (aq) --> Ni3(PO4)2 (s) + 6KCl (aq)
</span>
In the equation, 2 K3PO4 would react with 3 NiCl2. Then the calculation should be look like this:
V2= V1*m1/m2 *2/3
V2= 134ml * <span>0.0112/</span>0.225 *2/3
V2= 4.46ml
Answer:
0.8333 L. P1v1=p2v2
Explanation:
I dont now if this is wht you were looking for so srry
Answer:
Percent yield = 87.5%
Explanation:
Given data:
Number of moles of Fe(NO₃)₃ = 2.5 mol
Number of moles of Na₂CO₃ = 3.6 mol
Actual yield of NaNO₃ = 6.3 mol
Percent yield of NaNO₃ = ?
Solution:
Chemical equation:
2Fe(NO₃)₃ + 3Na₂CO₃ → Fe₂(CO₃)₃ + 6NaNO₃
now we will compare the moles of both reactant with NaNO₃.
Fe(NO₃)₃ : NaNO₃
2 : 6
2.5 : 6/2×2.5 = 7.5
Na₂CO₃ : NaNO₃
3 : 6
3.6 : 6/3×3.6 = 7.2
Theoretical yield of NaNO₃ is 7.2 mol.
Percent yield:
Percent yield = actual yield / theoretical yield ×100
Percent yield = 6.3 mol / 7.2mol ×100
Percent yield = 87.5%
