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Radda [10]
3 years ago
12

Mercury thermometers work because mercury ____ when it is warmed

Chemistry
1 answer:
kap26 [50]3 years ago
5 0
Mercury expands when it is heated. This process is called thermal expansion.
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For the following amino acids, draw a triangle around the amine group, draw a square around the carboxyl and circle the side gro
mylen [45]

hooc are carboxyl groups

your r or amino groups are those unique structures which have different atoms in them. your nh2 groups are your hydrogen atoms

4 0
3 years ago
You add 7.8 g of iron to 20.70 mL of water and observe that the volume of iron and water together is 21.69 mL . Calculate the de
bixtya [17]
21.69mL - 20.70mL = .99mL Fe
7.8 g / .99 mL = 7.9g/mL 
4 0
3 years ago
Determine if these molecules and ion are polar.
Colt1911 [192]

Answer:

a. Polar

b. Polar

c. Non-polar

d. Non-polar

Explanation:

a. H_3O^+, hydronium cation contains a positive charge. Just as any other ion, it is polar, as it has a net charge.

b. H_2S has the same shape as water. There are two lone pairs on sulfur atom which produce an overall dipole moment in this molecule, the bent structure is polar.

c. PCl_5 is non-polar, as the central atom, phosphorus, doesn't contain any lone pairs, all the dipole moments cancel out: two dipole moments in the vertical plane, P-Cl, and three P-Cl dipoles in the horizontal plane within a trigonal bipyramidal shape.

d. CF_4 is non-polar, since it's a tetrahedral molecule with no lone pairs on carbon atom, all four C-F dipole moments cancel out to yield a net 0 dipole moment.

3 0
3 years ago
Think about what would happen if this substance were first in the solid phase, then melted in a liquid. What can you say about t
alexira [117]

Answer:

The melting point of the solid is higher in temperature then it is compared to the freezing point of the liquid.

Explanation:

3 0
2 years ago
Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}

Given:

\left[I_2_{Equilibrium} \right] = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0
3 years ago
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