Convert 125m^3 to km^3

The output of a plant is 4335 pounds of ball bearings per week (5days) if each ball weighs .0113 g how many ball bearings does t

AfilCa [17]

The plant makes 3.50 × 10⁷ bearings per day

Pounds of bearings = 1 da × (4355 lb bearings/5 da) = 871.0 lb bearings

Grams of bearings = 871.0 lb bearings × (453.6 g bearings/1 lb bearings)

= 3.951 × 10⁵ g bearings

No. of bearings = 3.951 × 10⁵ g bearings × (1 bearing/0.0113 g bearing)

= 3.50 × 10⁷ bearings

5 0

3 years ago

Which metal was more reactive in water? How do you know?

Rom4ik [11]

Answer:

alkali metals

Explanation:

they all react vigorously or even explosively with cold water, resulting in the displacement of hydrogen.

6 0

3 years ago

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Caustic soda is 19.1 M NaOH and is diluted for household use. What is the household concentration if 10 mL of the concentrated s

olga nikolaevna [1]

Hello!

To calculate the household concentration of NaOH we need to use the dilution formula, clearing for M2, as you can see in the equation below:

$M1*V1=M2*V2 \\ \\ V2= \frac{M1*V1}{V2}$

Now, we input the values from the data we have onto this equation. M1=19,1 M; V1=10 mL; V2=400 mL, and solve the equation to get the result:

$V2= \frac{M1*V1}{V2}= \frac{19,1M*10mL}{400 mL}=0,48M$

So, the household concentration of NaOH will be 0,48 M

Have a nice day!

4 0

4 years ago

Chemistry: plz help me:D

Cloud [144]

Answer:

the amswer to number 5 is 18g/ mol and the answer to number 6 is 8

3 0

3 years ago

In the following experiment, a coffee-cup calorimeter containing 100 mL of H2O is used. The initial temperature of the calorimet

Arte-miy333 [17]

Answer:

The final temperature is 32.78°C

Explanation:

Step 1: Data given

Volume of water = 100 mL = 0.100 L

The initial temperature of the calorimeter is 23.0 ∘C.

Mass of CaCl2 = 5.80 grams

The heat of solution ΔHsoln of CaCl2 is −82.8 kJ/mol

Specific heat of calorimeter = 4.184 J/g°C

Step 2: Calculate moles CaCl2

Moles CaCl2 = mass CaCl2 / molar mass CaCl2

Moles CaCl2 = 5.80 grams / 110.98 g/mol

Moles CaCl2 = 0.0523 moles

Step 3: Calculate energy

Q = ΔH * moles

Q = 82.8 kJ/mol * 0.0523 moles

Q = 4.33 kJ

Step 4: Calculate change of temperature

Q = m*C*ΔT

⇒with Q = the energy needed = 4.33 kJ

⇒with m = the mass = 105.80 grams

⇒with C = the specific heat = 4.184 J/g°C

⇒with ΔT = the change of temperature = TO BE DETERMINED

ΔT = 4.330 J / (105.80 * 4.184 J/g°C)

ΔT = 9.78 °C

Step 5: Calculate the final temperature

ΔT = T2 - T1

9.78 °C = T2-23.0°C

T2 = 32.78 °C

The final temperature is 32.78°C

5 0

4 years ago