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qaws [65]
3 years ago
8

Convert 125m^3 to km^3

Chemistry
1 answer:
Ugo [173]3 years ago
4 0

Answer:

1.25e-7

Explanation:

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A mole is known by what other name?
Margarita [4]

Answer: avogadros number/constant

Explanation:

3 0
1 year ago
what is the product of sodium sulphate and magnesium phosphite if they were combined? please give the chemical formula not its n
Morgarella [4.7K]

Answer:

MgSO4  is right

Explanation:

6 0
3 years ago
Put the steps of the scientific method into the correct order.
Butoxors [25]

Answer:define propose devise state and then submit

5 0
3 years ago
A 13.00 g sample of a compound contains 4.15 g potassium (k), 3.76 g chlorine (cl), and oxygen (o). calculate the empirical form
MrRissso [65]

To solve this problem, let us all convert the mass of each element into number of moles using the formula:

moles = mass / molar mass

Where,

molar mass K = 39.10 g / mol

<span>molar mass Cl = 35.45 g / mol</span>

molar mass O = 16 g / mol

<span>and mass O = 13 g – 4.15 g – 3.76 g  = 5.09 g</span>

 

moles K = 4.15 g / (39.10 g / mol) = 0.106 mol

<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>

moles O = 5.09 g / (16 g / mol) = 0.318 mol

 

The ratio becomes:

0.106 K: 0.106 Cl: 0.318 O

We divide all numbers with the smallest number, in this case 0.106. This becomes:

K: Cl: 3O

 

Therefore the empirical formula is:

KClO_{3}

7 0
3 years ago
29.0g silver combine completely with 4.30g of sulfur to form a compound. what is the percent composition of this compound?
Deffense [45]

Answer:

Percentage of silver and sulphur in the compound  is 87.08% and 12.91%  respectively

Explanation:

Given:

Amount of silver = 29.0 g

Amount of sulphur= 4.30 g

To find:

Percent composition of the compound=?

Solution:

\text { percent of compound }=\frac{\text { amount of element }}{\text { Total Molecule Mass }} \times 100

Total Molecule mass = amount of silver + amount of sulphur

Total Molecule mass = 29+4.3  

Total Molecule mass = 33.3g

Percentage of silver:

\text { Percentage of silver }=\frac{\text { amount of silver }}{\text { Total Molecule Mass }} \times 100

=>\frac{29.0}{33.3}\times100

=>0.8708 \times100

=> 87.08%

Percentage of silver:

\text { Percentage of silver }=\frac{\text {amount of suplhur}}{\text { Total Molecule Mass }} \times 100

=>\frac{4.30}{33.3}\times 100

=>0.1291\times 100

=> 12.91%

3 0
3 years ago
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