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Yakvenalex [24]
1 year ago
15

The difference in an area with high concentration and an area with low concentration is called.

Chemistry
1 answer:
Varvara68 [4.7K]1 year ago
5 0

The difference in an area with high concentration and an area with low concentration is called the concentration gradient.

<h3>What is Concentration Gradient ?</h3>

A concentration gradient occurs when the concentration of particles is higher in one area than another.

In passive transport, particles will diffuse down a concentration gradient, from areas of higher concentration to areas of lower concentration, until they are evenly spaced.

This difference in an area with high concentration and an area with low concentration is called the concentration gradient.

Learn more about diffusion here ;

brainly.com/question/24746577

#SPJ1

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Radon-219 decays to radon-218 by releasing... a. a positron b.a muon O c. a neutron O d. an electron O e. a proton
MrRa [10]

Answer: Option (c) is the correct answer.

Explanation:

A positron is denoted as ^{0}_{+1}e, a neutron is denoted as ^{1}_{0}n, an electron is denoted as ^{0}_{-1}e, and a proton is denoted as ^{1}_{1}p.

Therefore, when ^{219}Rn will decay into ^{218}Rn this means there occurs decrease in its mass number. Hence, it means a neutron will be releasing during this reaction.

The reaction will be as follows.

                ^{219}Rn \rightarrow ^{218}Rn + ^{1}_{0}n

4 0
3 years ago
Transamination removes the amino group to form a carbon skeleton that contains
tangare [24]

Answer:

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Explanation:

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7 0
3 years ago
Read 2 more answers
To convert from liters/second to cubic gallons/minute, multiply the number of liters/second by 15.850 0 0.0353 00.2642 0 60
ivanzaharov [21]

Answer: 15.850

Explanation:

The conversion used from liters to gallons is:

1 L = 0.264172 gallon

The conversion used from sec to min is:

60 sec = 1 min

1 sec =\frac{1}{60}\times 1=0.017min

We are asked: liters/sec = gallons/min

liters/sec=\frac{0.264172}{0.017}=15.850gallons/min

Therefore, to convert from liters/second to gallons/minute, multiply the number of liters/second by 15.850.

8 0
3 years ago
Particle 1 has a velocity v1 = 2 m/s and a mass m1 = 2 kg . this particle collides with particle 2 of mass m2 = 6 kg , which is
creativ13 [48]
This follows the law of conservation of momentum. Momentum is the product of mass and velocity of object. 
Momentum = mass(m) x velocity(v) 
law of conservation of momentum means that the total momentum of system before the collision of 2 objects is equal to the total momentum after the collision 
Before the collision total momentum 
= m1v1 + m2v2
m1 = 2 kg
v1 = 2 m/s
m2 = 6 kg
v2 = 0 m/s
substituting the values in the equation 
total momentum before = (2 kg x 2 m/s) + (6 kg x 0 m/s)
total momentum = 4 kgm/s
after the collision the 2 objects stick together and have a common velocity 
total momentum after the collision  = (6 kg + 2 kg)x V  = 8V
V = speed of the conglomerate particle

since total momentum before is equal to total momentum after
8V = 4
V = 2 m/s
speed of conglomerate particle is 2 m/s
8 0
2 years ago
An inflatable toy starts with 1.05 moles of air and a volume of 5.17 liters. When fully inflated, the volume is 8.00 liters. If
padilas [110]

Answer:-  1.62 moles

Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.

\frac{V_1}{V_2}=\frac{n_1}{n_2}

from given data, V_1 = 5.17 L, n_1 = 1.05 moles

V_2 = 8.00 L, n_2 = ?

Let's plug in the values in the formula:

\frac{5.17L}{8.00L}=\frac{1.05moles}{n_2}

On cross multiply:

n_2=\frac{8.00L(1.05moles)}{5.17L}

n_2 = 1.62 moles

So, now the toy contains 1.62 moles of the air.


5 0
3 years ago
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