When 36x^4 + 12x^8 is divided by 12x^4, the result is

A pair of pants was 40% off the original price. The sale resulted in a $36 discount. What was the original price before the sale

Mama L [17]

Answer:

$90.00

Step-by-step explanation:

40% of What is 36?

40/4 = 10 (10%)

36/4 = 9 (9 is 10% of the answer we are looking for)

Multiply both answers (9 and 10) by each other.

You get 90

8 0

3 years ago

Bella's score on a spelling test is a function of the number of hours she studies. Which expression represents Bella's score on

Anna [14]

The correct answer is C

7 0

3 years ago

Read 2 more answers

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

What’s the answer show your WORK Plz

Yuliya22 [10]

Answer:

732.7 I think

Step-by-step explanation:

You just multiply 28 by 26.17

3 0

3 years ago

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At the start of the year a summer holiday to Spain cost £650. It increased by 11% in

olga nikolaevna [1]

Answer:

Final cost = £779

Step-by-step explanation:

It is given that:

Cost of summer holiday = £650

Amount increased by 11%

Increased cost = 11% of 650

Increased cost = $\frac{11}{100}*650$

Increased cost = 0.11 * 650 = £71.50

Amount after increment = 650 + 71.50 = £721.50

Further increase = 8%

Amount = 0.08 * 721.50 = £57.72

Final cost = 721.50 + 57.72 = £779.22

Thus,

Final cost = £779

5 0

3 years ago