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earnstyle [38]
2 years ago
6

The sum of 5.5 and twice a number is -10

Mathematics
2 answers:
elena-s [515]2 years ago
3 0
The answer is n= 7.75.
elena-s [515]2 years ago
3 0

Answer:

n=-7.75

Step-by-step explanation:

Based on the given conditions, formulate: 5.5+2×X=-10

Rearrange unknown terms to the left side of the equation:2x=-10-5.5

Calculate the sum or difference:2x=-15.5

Divide both sides of the equation by the coefficient of variable:x=-15.5/2

Multiply both the numerator and denominator with the same integer:-155/20

Cross out the common factor:-31/4

get the result:  -7.75

Answer: -7.75

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Explain how we know the number of zeros a polynomial has? Also, walk me through the process of finding all the zeros?
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Krishna has $4.90 with a combined 34 nickels and quarters. How many of<br> each coin does she have?
Oksana_A [137]

Answer:

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3 years ago
Assume that the helium porosity of coal samples taken from any particular seam is Normally distributed with true standard deviat
riadik2000 [5.3K]

Answer:

a) 4.85-2.33\frac{0.75}{\sqrt{20}}=4.46    

4.85+2.33\frac{0.75}{\sqrt{20}}=5.24    

b) 4.56-2.33\frac{0.75}{\sqrt{16}}=4.12    

4.56+2.33\frac{0.75}{\sqrt{16}}=4.99  

c) n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55

Step-by-step explanation:

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that z_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

4.85-2.33\frac{0.75}{\sqrt{20}}=4.46    

4.85+2.33\frac{0.75}{\sqrt{20}}=5.24    

Part b

4.56-2.33\frac{0.75}{\sqrt{16}}=4.12    

4.56+2.33\frac{0.75}{\sqrt{16}}=4.99  

Part c  

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.4/2 =0.2  we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55

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