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Troyanec [42]
3 years ago
12

7. Find the length of AB please answer will mark brainelist :)

Mathematics
1 answer:
Julli [10]3 years ago
7 0

Answer:

A) 17 m  B) 20.8 m

Step-by-step explanation:

I cannot mark on the image but you can find the length of A to the bottom of the shape by subtracting 26-11

26-11 = 15

I will label the triangle as ABC (AB the length we trying to find, BC is 15 *it is angle B to the intercept of A and the bottom of the shape, AC is 8 because it is parallel to the given length 8)

AB is the hypotenuse

We can use the pythagorean theorem  to find length AB (a^2 + b^2 = c^2)

a and b is the legs which is 8 and 15

8^2 + 15^2 = AB^2

64 + 225 = AB^2

289 = AB^2

√289 = AB (to undo a square, you use square roots)

√289 = 17

AB = 17 m

Now we need to find the hypotenuse of AC

the same thing, we did for problem A, use the pythagorean theorem

17^2 + 12^2 = AC^2

289 + 144 = AC^2

433 = AC^2

√433 = AC

√433 is <em>about </em>20.808...

round to the tenth as stated in the directions

AC = 20.8 m

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Answer:

x=30cm

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Step-by-step explanation:

From the question we are told that

Sides difference \triangle x= 5cm

Area difference  \triangle a=326sq.cm

Let first square be A

Let second square be B

Generally the area of a square is mathematically given by

Area of a squareA=x*x=x^2

Area of a squareB=(x+5)^2=x^2+25+10x

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Therefore from the equations above

x^2+25x+10-x^2=325

10x=325-25

x=300/10

x=30cm

Therefore

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Side of the second square.

y=>30+5=35cm

Check answer

35^2-30^2=325

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Step-by-step explanation:

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