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algol13
3 years ago
8

Please help I do not understand

Mathematics
1 answer:
pogonyaev3 years ago
8 0

Answer:

-3/7

Step-by-step explanation:

Hi,

First of all, we know that the slope is not undefine because both the x-coordinates are not the same.

To find the slope, do change in y/change in x. Here, it would be ((2/7)-(5/7))/(2-1) or (-3/7)/1. Hence, the slope is -3/7.

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-onsider x + 4 = x + 8. What values could be substituted for x to make this a true
devlian [24]

Answer:

No because upon subtracting x on both sides you obtain a false equation of 4=8.

The problem:

What are x values that satisfy:

x+4=x+8?

Step-by-step explanation:

No number can be substituted into x+4=x+8 to make it true.

There is no number that you can find such that when you add 4 to it will give you the same as adding 8 to it.

Also if you subtract x on both sides you obtain the equation 4=8.

4=8 is not true so x+4=x+8 is never true for any x.

7 0
4 years ago
PLSSSSSSS ASAPPPPPPPP<br><br><br> A)157<br> B)67<br> C)177<br> D)None of these answers <br> E)23
Helga [31]
23 is the answer for the problem
5 0
3 years ago
Read 2 more answers
An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo
Andrew [12]
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.

Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.

Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7 

Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18

Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.

Answer: 37,39,41,43

8 0
3 years ago
How much smaller is the sum of the first 1000 natural numbers than the sum of the first 1001 natural numbers?
aleksandr82 [10.1K]

ANSWER

1001

EXPLANATION

The sum of the first n - natural numbers is

S_n=  \frac{n}{2} (2a + d(n - 1))

The sum of the first 1000 terms is

S_{1000}=  \frac{1000}{2} (2(1) + 1(1000 - 1))

S_{1000}=500 (1001)

S_{1000}=500500

The sum of the first 1001 terms is

S_{1001}=  \frac{1001}{2} (2(1) + 1(1001 - 1))

S_{1001}= 1001 \times (501)

= 501501

The difference is

501501 - 500500= 1001

5 0
3 years ago
Read 2 more answers
The total area of the figure below is (blank) units look at picture to solve
Tpy6a [65]
9x4=36 squared units
3 0
3 years ago
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