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Valentin [98]
2 years ago
9

IM DESPERATE

Mathematics
1 answer:
telo118 [61]2 years ago
7 0
You can scan it on brainly, It’ll help you
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How many Dimes and Quarters
8_murik_8 [283]

Answer:

Julian has <em>16 dimes</em> and <em>6 quarters</em>

Step-by-step explanation:

Let's suppose Julian has q quarters and d dimes

The total coins are 22, that is

q+d=22

q=22-d   [1]

The total amount of money he has is 310 cents which are made of 10d dimes and 25q quarters

10d+25q=310

Simplifying by 5

2d+5q=62

Using the relation [1]

2d+5(22-d)=62

2d+110-5d=62

3d=48 => d=16

q=22-16 = 6

So Julian has 16 dimes and 6 quarters

5 0
3 years ago
Round 97.081 to the nearest 10th
Travka [436]

Answer:97.1

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is the slope of the line<br>​
charle [14.2K]

Answer:

The slope is -1/1 or just -1.

(When you need to plot the slope, you use -1/1 to use the strategy Rise/Run or Rise over Run.

If you look at the point (-3,1) From that point, you go down -1 and you run to the side for a positive 1.

Once you do that you'll land at (-2,0) and you can keep on repeating this and you'll see that it lands on the points on the line.

Hope this helps! Please feel free to ask any questions if needed! :)

4 0
2 years ago
If you know the answer to this, please say it! Equation and all too! Thank you :DD
vlabodo [156]

Answer

x=33

Step-by-step explanation:

since they're both on the same line we must equal them to 180.

18 + x + 4x -3 = 180 (Now you simplify terms)

5x + 15 = 180 (Subtract the 15 from both sides)

5x = 165 (divide by 5 to isolate the variable)

x = 33 (Hope I was able to help :) )

6 0
2 years ago
A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups
HACTEHA [7]

Answer:  b. 8.56 to 21.44

Step-by-step explanation:

Let  \mu be the  mean number of pushups that can be done.

As per given , we have

Sample size : n= 10

Degree of freedom = n-1=9

Sample mean : \overline{x}=15

Sample standard deviation : s=9

Significance level : α=1-0.95=0.05

From t- distribution table ,

Critical two -tailed t-value for α=0.05 and df = 9 is

t_{\alpha/2, 9}=t_{0.025,9}=2.2622

Confidence interval for \mu is given by :-

\overline{x}\pm t*\dfrac{s}{\sqrt{n}}

=15\pm (2.2622)\dfrac{9}{\sqrt{10}}\\\\\approx 15\pm 6.44=(15-6.44,\ 15+6.44)\\\\=(8.56,\ 21.44)

Hence, the  95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.

5 0
2 years ago
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