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kotykmax [81]
3 years ago
11

If a 1,000-kg car is traveling at 20.0 m/s when it reaches the bottom of a circular hill of radius 8.00 m, what normal force doe

s the road exert on the car at the bottom of the hill
Physics
1 answer:
scoray [572]3 years ago
6 0

Answer:

i don't know this one.

Explanation:

You might be interested in
The lamp cord is 85cm long and comprises cupper wire. Calculate the wire‘s resistance?
DaniilM [7]

Answer:

R = 0.0015Ω

Explanation:

The formula for calculating the resistivity of a material is expressed as;

ρ = RA/l

R is the resistance

ρ is the resistivity

A is the area of the wire

l is the length of the wire

Given

l = 85cm = 0.85m

A = πr²

A = 3.14*0.0018²

A = 0.0000101736m²

ρ = 1.75 × 10-8Ωm.

Substitute into the formula

1.75 × 10-8 = 0.0000101736R/0.85

1.4875× 10-8 = 0.0000101736R

R = 1.4875× 10-8/0.0000101736

R = 0.0015Ω

3 0
3 years ago
In a Broadway performance, an 83.0-kg actor swings from a R = 3.90-m-long cable that is horizontal when he starts. At the bottom
Veseljchak [2.6K]

Answer:

h = 2.821\,m

Explanation:

The speed of the actor before the collision is found by means of the Principle of Energy Conservation:

(83\,kg)\cdot(9.807\,\frac{m}{s})\cdot (3.90\,m) = \frac{1}{2}\cdot (83\,kg)\cdot v^{2}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (3.90\,m)}

v \approx 8.746\,\frac{m}{s}

The speed after the inelastic collision is obtained by using the Principle of Momentum Conservation:

(83\,kg)\cdot (8.746\,\frac{m}{s} )+(55\,kg)\cdot (0\,\frac{m}{s} ) = (83\,kg + 55\,kg)\cdot v

v = 5.260\,\frac{m}{s}

Lastly, the maximum height is determined by using the Principle of Energy Conservation again:

\frac{1}{2}\cdot (138\,kg)\cdot (5.260\,\frac{m}{s} )^{2} = (138\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot h

h = \frac{(5.260\,\frac{m}{s} )^{2}}{9.807\,\frac{m}{s^{2}} }

h = 2.821\,m

8 0
3 years ago
Did the bird population appear to benefit from the elimination of the rattlesnakes
Maurinko [17]
Yes because there's less rattlesnakes to eat them

  ~~~hope this helps~~~
~~have a beautiful day~~
            ~davatar~
7 0
3 years ago
A supercapacitor is an electrical energy storage device. A supercapacitor, initially charged to 2.1 thousand millivolts, supplie
svet-max [94.6K]

Answer:

the time taken t is 9.25 minutes

Explanation:

Given the data in the question;

The initial charge on the supercapacitor = 2.1 × 10³ mV = 2.1 V

now, every minute, the charge lost is 9.9 %  

so we need to find the time for which the charge drops below 800 mV or 0.8 V

to get the time, we can use the formula for compound interest in basic mathematics;

A = P × ( (1 - r/100 )ⁿ

where A IS 0.8, P is 2.1, r is 9.9

so we substitute

0.8 = 2.1 × ( 1 - 0.099 )ⁿ

0.8/2.1 = 0.901ⁿ

0.901ⁿ = 0.381

n = 9.25 minutes

Therefore, the time taken t is 9.25 minutes

6 0
3 years ago
Potential difference is measured in units called
Masja [62]

Answer: Volt

Explanation:

5 0
3 years ago
Read 2 more answers
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