Answer:
The wavelength of the radiation absorbed by ozone is 319.83 nm
Explanation:
Given;
frequency of absorbed ultraviolet (UV) radiation, f = 9.38×10¹⁴ Hz
speed of the absorbed ultraviolet (UV) radiation, equals speed of light, v = 3 x 10⁸ m/s
wavelength of the absorbed ultraviolet (UV) radiation, λ = ?
Apply wave equation for speed, frequency and wavelength;
v = fλ
λ = v / f
λ = (3 x 10⁸) / (9.38×10¹⁴)
λ = 3.1983 x 10⁻⁷ m
λ = 319.83 x 10⁻⁹ m
λ = 319.83 nm
Therefore, the wavelength of the radiation absorbed by ozone is 319.83 nm
Answer:
26.83 N.
Explanation:
If the angle between two vector is 90°, to get the resultant, we use Pythagoras theorem.
a² = b²+c²......................... Equation 1
Where a = R = Resultant, b = 12 N, c = 24 N.
Substitute these values into equation 1
R² = 12²+24²
R² = 144+576
R² = 720
√R² = √720
R = 26.83 N.
Hence, the result of the two force is 26.83 N.
The Kelvin scale has no negatives on it.
Zero Kelvin is 'Absolute Zero', and nothing can get colder than that.
Answer:
Part a)
Part b)
So this speed is independent of the mass of the rider
Explanation:
Part a)
By force equation on the rider at the position of the hump we can say
now we will have
now we have
Part b)
At the top of the loop if the minimum speed is required so that it remains in contact so we will have
at minimum speed
So this speed is independent of the mass of the rider
