Answer:
time rising = 34 / 9.8 = 3.47 sec
total time in air = 2 * 3.47 sec = 6.94 sec
(time rising must equal time falling)
R = 17 m/s * 6.94 s = 118 m
Can also use range formula
R = v^2 sin (2 theta) / g
tan theta = 34 / 17 = 2
theta = 63.4 deg
2 theta = 126.9 deg
sin 126.9 = .8
v^2 = 17^2 + 34^2 = 1445 m^2/s^2
R = 1445 * .8 / 9.8 = 118 m agreeing with answer found above
Answer:
sEE BELOW
Explanation:
Well.....because the numbers are 'astronomical'....meaning VERY, VERY , VERY LARGE
Faster than. Hope this helps!!!
1. Tangential velocity:
<em>e) the instantaneous velocity of a body moving in a circular path.</em>
2. Parabolic pathway
<em>c. a curved path followed by projectiles</em>
3. Projectile
<em>d) an object projected through space, traveling in two dimensions, that accelerates vertically due to gravity.</em>
4. Centripetal acceleration
<em>a) acceleration towards the center caused by the centripetal force</em>
5. Centripetal force
<em>b) a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the center</em>
Answer:
v = 16.11 m / s
Explanation:
For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation
starting point. When the spring is compressed
Em₀ = K_e + U = ½ k x² + m g x ’
final point. The point where it leaves the platform
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
½ k x² + m g x ’= ½ m v²
v² = 
x² + g x
let's calculate
v² = 
1.25² + 9.8 1.25
v² = 247.159 + 12.25 = 259.409
v = 16.11 m / s
