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Serhud [2]
3 years ago
15

A swimmer takes 45 seconds to complete a 100-meter lap. Calculate the swimmer’s average speed.

Physics
2 answers:
g100num [7]3 years ago
5 0
2.22 m/s. Average speed is Total distance over time it took. 100m/45s = 2.22m/s
Sedaia [141]3 years ago
3 0

Answer:

Swimmer's velocity, v = 2.23 m/s

Explanation:

It is given that,

Distance, d = 100 meter

Time taken by the swimmer, t = 45 seconds

We have to find the average speed of the swimmer. Average speed is equal to total distance divided by total time taken i.e.

v=\dfrac{d}{t}

v=\dfrac{100\ m}{45\ s}

v = 2.23 m/s

So, the velocity of the swimmer is 2.23 m/s. Hence, this is the required solution.

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Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its
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a

The orbital speed is v= 2.6*10^{3} m/s

b

The escape velocity of the rocket is  v_e= 3.72 *10^3 m/s

Explanation:

Generally angular velocity is mathematically represented as

            w = \frac{2 \pi}{T}

Where T is the period which is given as 1.6 days = 1.6 *24 *60*60 = 138240 sec

       Substituting the value

         w = \frac{2 \pi}{138240}

             = 4.54*10^ {-5} rad /sec

At the point when the rocket is on a circular orbit  

   The gravitational force =  centripetal force and this can be mathematically represented as

              \frac{GMm}{r^2} = mr w^2

Where  G is the universal gravitational constant with a value  G = 6.67*10^{-11}

            M is the mass of the earth with a constant value of M = 5.98*10^{24}kg

            r is the distance between earth and circular orbit where the rocke is found

               Making r the subject

                     r = \sqrt[3]{\frac{GM}{w^2} }

                        = \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }

                        = 5.78 *10^7 m

The orbital speed is represented mathematically as

                   v=wr

Substituting value

                  v= (5.78*10^7)(4.54*10^{-5})

                     v= 2.6*10^{3} m/s    

The escape velocity is mathematically represented as

                            v_e = \sqrt{\frac{2GM}{r} }

Substituting values

                             = \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }

                             v_e= 3.72 *10^3 m/s

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